How Do You Calculate the Average Force of Air Resistance on a Projectile?

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Homework Help Overview

The discussion revolves around calculating the average force of air resistance acting on a projectile shot vertically upward. The original poster presents a scenario involving a projectile with a specified mass and initial velocity, seeking to understand the impact of air resistance on its maximum height.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between potential energy and work done by air resistance, questioning the application of the work-energy principle. There is a focus on the differences in maximum potential energy between two scenarios.

Discussion Status

Some participants have provided insights into the calculations and concepts involved, while others express confusion regarding the application of trigonometric identities in the context of work done by air resistance. The discussion reflects a mix of attempts to clarify the problem and explore different interpretations of the equations involved.

Contextual Notes

There is mention of potential confusion due to the complexity of the problem and the effects of air resistance on the projectile's motion. Participants are also navigating through the implications of using different values in their calculations.

neoncrazy101
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Homework Statement


A projectile of mass 0.656 kg is shot straight up with an initial speed of 25.4 m/s. (a) How high would it go if there were no air resistance? (b) If the projectile rises to a maximum height of only 7.64 m, determine the magnitude of the average force due to air resistance.

Homework Equations


1/2mvf^2 + mghf = 1/2mvo^2 + mgho

Work = KE+ PE
W = Fcos(90)s

The Attempt at a Solution



Ok, I am able to get the answer for A: (32.9m) but with B, I cannot get it. What should I do to get the answer for B? Whenever I put the equation into W = Fcos(90)s I come up with zero which is not the answer. So I don't know what I'm doing wrong.
 
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Well, cos(90) = 0 (some sort of trig identity I suppose), so your equation for the work done by the air resistance is wrong. Looking at the problem, the projectile is shot straight up, and the air resistance acts to retard this motion. The reduction in trajectory height would be similar to using the same effort to launch a heavier projectile upward.
 
neoncrazy101 said:
Ok, I am able to get the answer for A: (32.9m) but with B, I cannot get it. What should I do to get the answer for B? Whenever I put the equation into W = Fcos(90)s I come up with zero which is not the answer. So I don't know what I'm doing wrong.
What is the work done by air resistance? (hint: what is the difference in maximum potential energy between A and B?).

Now if that work is done by a constant force over the distance that the projectile moves, what is that force?

AM
 
The difference in PE between A and B is 49.116032.

I'm probably very very confused (most likely, brain is fried plus headache) but if I take that 49.116032 and multiply it by the 7.64m then I come with up 375.2 which is really large.

EDIT: I figured it out! W=162.50248 (roughly) and then F = W/D thus 162.50248/7.64 = 21.3ish.
 
Last edited:
neoncrazy101 said:
The difference in PE between A and B is 49.116032.

I'm probably very very confused (most likely, brain is fried plus headache) but if I take that 49.116032 and multiply it by the 7.64m then I come with up 375.2 which is really large.

EDIT: I figured it out! W=162.50248 (roughly) and then F = W/D thus 162.50248/7.64 = 21.3ish.
How did you get this value for W? (you should show your work). What are the units of force?

AM
 

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