How Do You Calculate the Design Angle θ for Strut AB in Vector Problems?

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Rybka
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Homework Statement



"Determine the design angle θ (0° ≤ θ ≤ 90°) for strut AB so that the 400-lb horizontal force has a component of 500lb directed from A towards C. What is the component of force acting along member AB? Take ϕ = 40°"


Homework Equations



x-component: magnitude*cos(θ)
y-component: magnitude*sin(θ)

The Attempt at a Solution



I understand what is being asked, I'm just unsure as to how I would get that AC component with what is given.

-Rybka
 
Attachments
  • Diagram of a two-member truss: strut AB runs from pin A at upper left to pin B on a vertical wall at right, strut AC runs from A down to pin C on a horizontal floor. A 400 lbs horizontal force points left at A. Angle θ is marked between strut AB and a dashed horizontal line, and angle ϕ is marked between strut AB and strut AC.
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Hi Rybka. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Take ϕ = 40°
Please correct this.

You have 3 forces, they must form a closed triangle. Struts exert their force in line with their length, so this tells you the directions of their contributions.

Are you given the correct answer?
 
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Good evening!

The solution is: θ = 53.5°, ForceAB = 621lb
 
I figured it out.

The position of the struts in the first diagram is confusing, but the fact that we're solving for θ means their shape is variable.

Once I moved things around a little bit, it all became clear. :smile:
 
Attachments
  • Left: a bracket with a horizontal 400lbs force arrow at joint A, strut AB at angle θ to a dashed horizontal, and angle φ between AC and AB. Right: force triangle with F_AB, F_AC, 400lbs and labels θ and φ.
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Rybka said:
The solution is: θ = 53.5°, ForceAB = 621lb
It's always useful to know the answer. I was hoping you'd edit your post so it tells us exactly what is 40°. That would be useful for someone following along.

Good to know you worked it out.
 
The problem in the drawing does not give accurate dimensions
 
Attachments
  • Handwritten student notes with a statics diagram: a 400 lb horizontal force at point A, strut AB to a wall at B, member AC to a floor support at C, angle theta marked at A, and a force triangle below with F_AB and F_AC labels.
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  • Handwritten force diagram with a resultant FR = 400 lb pointing left, force FAC = 500 lb along AC, unknown FAB along the strut AB, and angle θ and angle 40° marked at C; Arabic notes and sine-law steps follow, solving sin θ = 0.8034 and FAB = 621.15 lb.
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