How Do You Calculate the Eccentricity of an Elliptical Orbit?

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Discussion Overview

The discussion revolves around calculating the eccentricity of an elliptical orbit, specifically in the context of a spacecraft's trajectory around the Earth and Mars. Participants explore the necessary parameters and formulas needed for this calculation.

Discussion Character

  • Technical explanation, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant provides gravitational parameters for the Sun, Earth, and Mars, along with the semi-major axis of the orbit.
  • Another participant suggests that knowing the aphelion distance and the length of the major axis can help determine the perihelion distance, which is necessary for calculating eccentricity.
  • A later reply indicates that the aphelion of the spacecraft corresponds to the radius of Earth's orbit and notes that the sum of aphelion and perihelion equals the length of the major axis.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method for calculating eccentricity, and multiple approaches are suggested without resolution.

Contextual Notes

The discussion lacks specific values for aphelion and perihelion distances, which are critical for calculating eccentricity. There is also a dependence on the definitions of these terms, which may vary.

Dustinsfl
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##\mu_{sun} = 132712000000##
##\mu_{earth} = 398600##
##\mu_{mars} = 42828##
##R_{earth} = 149.6\times 10^6##
##R_{mars} = 227.9\times 10^6##
##r_{earth} = 6378##
##r_{mars} = 3396##

The spacecraft will make 3 rev in 2 Earth years. I found the semi-major axis of the ellipse which is
$$
a = 1.14162979\times 10^8
$$
How can I determine the eccentricity of the ellipse with this information? I have been looking at every formula but can figure it out.

http://img20.imageshack.us/img20/182/orbit2.png
 
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If you know the aphelion distance and the length of the major axis then you can determine the perihelion distance. Having both ra and rp you can determine eccentricity.
 
I wasn't thinking thanks.
 
From your drawing the aphelion of the spacecraft is the same as the radius of Earth's orbit.
And the sum of aphelion and perihelion is equal to the length of the major axis.
 

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