How Do You Calculate the Equation of an Hourglass Curve?

  • Thread starter Thread starter ssj5harsh
  • Start date Start date
  • Tags Tags
    Curve
Click For Summary
SUMMARY

The discussion focuses on calculating the equation of an hourglass curve, specifically for a horizontally oriented hourglass with known diameter and height. Participants propose a combination of eight mathematical functions to represent the curve in three dimensions, utilizing cubic terms of y and z. The equations provided include variations of f(y,z) and x equations, which incorporate parameters such as height (h), annular radius (a), and a height-to-width coefficient (n). The discussion emphasizes the need for scaling and experimental adjustments to accurately model the sand flow.

PREREQUISITES
  • Understanding of cubic functions and their graphical representations
  • Familiarity with 3D coordinate systems and transformations
  • Knowledge of mathematical modeling techniques for fluid dynamics
  • Basic principles of geometry related to conical shapes
NEXT STEPS
  • Research cubic function properties and their applications in 3D modeling
  • Explore mathematical modeling for fluid dynamics in containers
  • Learn about scaling techniques in geometric representations
  • Investigate the impact of different materials on flow rates in hourglass designs
USEFUL FOR

Mathematicians, engineers, and designers interested in fluid dynamics, geometric modeling, and the practical applications of cubic equations in real-world scenarios.

ssj5harsh
Messages
45
Reaction score
0
I need to find the equation of the curve of an hourglass. Known: diameter, height. Time taken for the sand to be completely emptied is 1 minute. I would like it if someone would tell me where or how to start. I can't think of anything.

Thanks in advance.
 
Physics news on Phys.org
The curve of an hourglass? An hourglass can be many different shapes, starting with a cone. The information you give as "known" has nothing to do with the shape.
 
i was looking for the same thing today and came across this question

what i came up with was a combination of 8 functions for a 3d representation, although i am not certain if they are correct. also of note is that this is for it laying on its side. anyway, here goes:

x = y3 + z3 + 1, For x, 0 to h
-x = y3 + z3 + 1, For x, -h to 0
-x = -y3 + z3 + 1, For x, -h to 0 (?)
x = -y3 + z3 + 1, For x, 0 to h (?)
x = y3 + z3 - 1, For x, -h to 0
-x = y3 + z3 - 1, For x, 0 to h
-x = -y3 + z3 - 1, For x, 0 to h (?)
x = -y3 + z3 - 1, For x, -h to 0 (?)

where 2h = height of hourglass

from here it (should) should just be a matter of scaling, choosing of sand, and experimental trial and error to come up with the correct amount of the particularly chosen sand.

again, am not sure if this is correct. . . .

Best Regards,
 
Last edited:
whoops, let's try this again. . . .

f(y,z) = n(y3 + z3) + a; For y = 0, and positive y; For x, 0 to h
f(y,z) = n(-y3 - z3) - a; For negative y; For x, -h to 0
f(y,z) = n(y3 - z3) - a; For negative y; For x, -h to 0
f(y,z) = n(-y3 + z3) + a; For y = 0, and positive y; For x, 0 to h
f(y,z) = n(y3 + z3) - a; For negative y; For x, 0 to h
f(y,z) = n(-y3 - z3) + a; For y = 0, and positive y; For x, -h to 0
f(y,z) = n(y3 - z3) + a; For y = 0, and positive y; For x, -h to 0
f(y,z) = n(-y3 + z3) - a; For negative y; For x, 0 to h

where h = 1/2 hourglass height,
a = the cubed root of the hourglass annulous radius,
and
n = a height to width coefficient
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 64 ·
3
Replies
64
Views
6K