How Do You Calculate the Force Needed to Turn a Pulley System?

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SUMMARY

The calculation of the force required to turn a pulley system involves understanding the relationship between torque, weight, and radius. The formula derived from the discussion is F = (m1 + m2)gr/R, where F is the force, m1 and m2 are the weights being lifted, g is the acceleration due to gravity, r is the radius of the pulleys, and R is the distance from the spindle to the handle. This approach utilizes energy conservation principles and torque calculations to determine the necessary force for rotation.

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hie everybody, this is my first post on this interesting site... :biggrin:
i am not sure how do i count the amount of force needed to turn such a pulley from the spindle attached to the dowel through the spindle. the pulleys are fixed to the dowel and are not movable. they just turn as the rope binds them together.
the groove of the spindle is layed with a layer of elastic band so that the thin rope doesn't slip of the spindle when span. The front part of both the dowels are each lifting a different amount of weight.
how do i count amount of force needed to spin from the spindle? what is the theory behind this? an illustration is attached to this thread. thanks a million... :smile:
 

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One way to tackle this problem is energy conservation. I assume this is a homework problem?
 
energy conversation? i guess is that hooke's law right?
but i am only a high school student and i haven't learn this yet. can u explain and show to me a little more please?
this is not my homework. i asked this because i did an artefact which is similar to what i had drawn in the diagram and would like to know how much work done i have to apply to turn the spindles with 2 loads and find it interesting as well. :-p
 
I have thought of a solution. But i don"t know whether this is correct or not. But u can try and work out on this.


If we assume both the pulleys have same radius (r) one roll of each pulley must lift the masses by a distance 2-pi-r. so the energy stored in the system is (m1+m2)g.2-pi-r for one rotation. If the distance of the handle of rotation of the spindle is R and the force required for rotation is F, the the torque required is F.R and the work done to rotate a full rotation is F.R. 2-pi. It follows that ,
F.R. 2-pi = (m1+m2)g. 2-pi-r
or, F.R = (m1+m2)gr
So, F = (m1+m2)gr/R
Now put the values and see the results if it tallies.
 

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