How Do You Calculate the Higher Temperature in a Chemical Kinetics Problem?

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The discussion focuses on calculating the higher temperature in a chemical kinetics problem involving a reaction with an activation energy of 54.0 kJ/mol. The rate constant increases by a factor of 7.00 when the temperature rises from 22 degrees Celsius. Participants suggest using the Arrhenius equation, ln(k) = -Ea/RT + ln(A), to relate the rate constants and temperatures, emphasizing the need to manipulate the equation to isolate the new temperature (T2).

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1. A certain reaction has an activation energy of 54.0 kJ/mol. As the temperature is increased from 22degrees celsius to a higher temperature, the rate constant increases by a factor of 7.00. Calculate the higher temperature.

2. ln(k)=-Ea/RT + ln(A)



3. i don't think that i have enough information because when i plugged the values given and there are still two variables. Then i tried simultanious equations by solving for [A] and there are still two variables the new temp and the rate constant. So if anyone can help it would be very appreciated.
 
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The rate constant is just 7 times the original rate constant, so can't you relate the two together as K1 and 7.K1, and then if you solve for T2 you should be able to get the K1s and the As to cancel out.
 

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