How Do You Calculate the Index of Refraction in a Light Refraction Problem?

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To calculate the index of refraction of the plastic, apply Snell's law, which states that n1sin(θ1) = n2sin(θ2). The angles of incidence and refraction are not equal but are related through the geometry of the setup. The first angle of incidence (44.0°) and the second angle of refraction (79.0°) must be used to find the index of refraction by solving the equations for each interface. Additionally, to determine the time it takes for the light ray to travel through the plastic, consider the distance and speed of light in the material. Understanding the relationship between the angles and applying the correct trigonometric relationships is essential for solving the problem accurately.
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Homework Statement



A light ray enters a rectangular block of plastic at an angle 1 = 44.0° and emerges at an angle 2 = 79.0°, as shown in Figure P22.61.
p35-71.gif


Figure P22.61
(a) Determine the index of refraction of the plastic.
wrong check mark
(b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, how long does it take the light ray to travel through the plastic?
ns


Homework Equations


n1sin(1)=n2sin(2) or sin(critical)=n2/n1

The Attempt at a Solution


i attempted arcsin(11/44) and arcsine(79/44) but both were wrong. Can someone please help me get on the right path?
 
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Treat this as two refractions and apply Snell's law at each interface. Hint: How does the second angle (the angle of refraction) at the first interface relate to the first angle (angle of incidence) at the second interface?
 
I have sin(44)=nsin(theta2) and sin(79)=nsin(theta2) but that cannot be correct. I know that the angle of incidence and angle of refraction are equal. Please help I am mising something here.
Thanks
 
floridianfisher said:
I have sin(44)=nsin(theta2) and sin(79)=nsin(theta2) but that cannot be correct.
True, that cannot be correct, since \sin 44 \neq \sin 79.
I know that the angle of incidence and angle of refraction are equal.
They are related, but not equal.

For clarity, I'll rewrite the equations as:
\sin 44 = n \sin \theta_a
\sin 79 = n \sin \theta_b

Find the simple trignometric relationship between \theta_a & \theta_b by examining the diagram. Look for triangles.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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