How do you calculate the line integral of f(x,y,z) from (1,2,3) to (0,-1,1)?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the line integral of the function f(x,y,z) = x+y+z over a straight-line segment from the point (1,2,3) to (0,-1,1). Participants are exploring the implications of different parameterizations and the significance of the resulting values.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the parameterization of the line segment and its impact on the integral's value. Questions are raised about the correctness of the parameterization and the interpretation of positive and negative results. There is also inquiry into the path independence of the line integral.

Discussion Status

The discussion is active with participants questioning the meaning of the results and the necessity of direction in the integral. Some participants are seeking clarity on the parameterization and its implications, while others are exploring the concept of path independence.

Contextual Notes

There is mention of potential confusion regarding the starting point for the parameterization and how it affects the integral's value. Participants are also considering the implications of moving from one point to another in the context of the line integral.

dwn
Messages
165
Reaction score
2

Homework Statement



Find the line integral of f(x,y,z) = x+y+z over the straight-line segment from (1,2,3) to (0,-1,1).

Homework Equations



∫ f(x,y,z)ds = ∫ f(g(t), h(t), k(t)) |v(t)| dt

The Attempt at a Solution



I arrived at the correct solution, but I'd like some clarity on the result.

The final answer to this is 3√(14) or -3√(14) depending on which point you choose as your parametric equation.
x = -t
y = -3t-1
z = -2t+1
From using the point (0,-1,1) and (-1,-3,-2) as my direction vector.

What I would like to understand is the meaning of the positive and negative result. Does it matter?
It just seems to me that my result should have been positive since I am moving from a lower position to a higher position, no?BTW, QUICK SHOUTOUT TO PF --- THE NEW SITE IS AMAZING! GREAT JOB ON THE NEW LAYOUT.
 
Physics news on Phys.org
dwn said:

Homework Statement



Find the line integral of f(x,y,z) = x+y+z over the straight-line segment from (1,2,3) to (0,-1,1).

Homework Equations



∫ f(x,y,z)ds = ∫ f(g(t), h(t), k(t)) |v(t)| dt

The Attempt at a Solution



I arrived at the correct solution, but I'd like some clarity on the result.
Which is the correct solution? You show 2 different values below.
The final answer to this is 3√(14) or -3√(14) depending on which point you choose as your parametric equation.
x = -t
y = -3t-1
z = -2t+1
From using the point (0,-1,1) and (-1,-3,-2) as my direction vector.

How did you arrive at this parameterization for the line segment specified? For example, if t = 0, does your parameterization return the (x,y,z) of the first point on the line segment?

What I would like to understand is the meaning of the positive and negative result. Does it matter?

Yes, it matters. Some line integrals are path independent. Is this one?

It just seems to me that my result should have been positive since I am moving from a lower position to a higher position, no?

How did you arrive at this conclusion? The OP states that the line integral is to be taken over the line segment from (1,2,3) to (0,-1,1), not the other way around.
 
Correct Answer: 3√(14) but I got the negative term because I used the wrong point as my starting position.Why does direction of the integral matter though? Because the value of the integral will remain the same. I see that they are asking us to go from a specified point and not the other, but is it really necessary?
 
Last edited:
Is ##\int_{a}^{b} f(x) dx = \int_{b}^{a} f(x) dx ## ?
 
No it is not.

I actually have a question about a and b though. How do we determine the interval? I still don't quite understand that.
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
3K
Replies
12
Views
5K
Replies
2
Views
2K