How Do You Calculate the Mass and Runway Distance for a Lufthansa A320?

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SUMMARY

The mass of a Lufthansa A320, given its acceleration and thrust, is calculated to be 70,557.61 kg using the equation F = ma, where the total thrust from two engines is 206,000 N. The distance traveled down the runway before lift-off is determined to be 912.38 m using the corrected formula D = Vit + 0.5at². The initial acceleration was calculated as 2.9196 m/s² based on the lift-off speed of 72.99 m/s over 25 seconds. Proper unit conversion and application of the equations of motion are critical for accurate results.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with kinematic equations for uniformly accelerated motion
  • Knowledge of unit conversions (e.g., kN to N)
  • Basic algebra for solving equations
NEXT STEPS
  • Review kinematic equations, specifically D = Vit + 0.5at²
  • Practice unit conversions, particularly between kilonewtons and newtons
  • Explore real-world applications of Newton's laws in aviation
  • Study the principles of thrust and drag in aircraft performance
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Aerospace engineering students, physics learners, and anyone interested in the calculations involved in aircraft dynamics and performance analysis.

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Homework Statement



A Lufthansa A320 accelerates from rest to lift-off speed of 72.99 m/s in 25.00 s. Each of the plane's two jet engines provides a forward force (thrust) of 103.00 kN. What is the mass of the plane?

How far does it travel down the runway before lift-off?

2. Governing equations
Vf=Vi+at
EF=ma
D=Vit+at^2

The Attempt at a Solution


Vf=72.99
Vi=0
a=?
t=25.00s
I used Vf=Vi+at to get a=2.9196
then EF=ma to solve for mass and got 35.27880532 which i was told was wrong i went back and looked at the problem and thought that since the plane has two engines i would double the mass, but it was still wrong. and i tried D=Vit+at^2 for the second problem, but it didn't work either i don't understand what I'm doing wrong. any help would be appreciated
 
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Cole07 said:

The Attempt at a Solution


Vf=72.99
Vi=0
a=?
t=25.00s
I used Vf=Vi+at to get a=2.9196
So far, so good. (Don't forget units.)
then EF=ma to solve for mass and got 35.27880532 which i was told was wrong i went back and looked at the problem and thought that since the plane has two engines i would double the mass, but it was still wrong.
F = ma is the right approach. But what's the total F? There are two engines, each giving their own force. And be careful with units: 1 kN = 1 kilo-N = 1000 N.
 
I think it should read like this:

103kN x 2 = 206kN
206kN = 206000 Newtons (N)

F=ma

206000 N = (m) (2.9196 m/s^2)

m = 206000 N / 2.9196 m/s^2
 
ok i got the mass of the plane to be 70557.61063kg, but i still don't know what I'm doing wrong to get the distance traveled down the runway.
 
d = (1/2)(vi + vf)(t)
 
i got it 912.375m thank you!
 
Cole07 said:
ok i got the mass of the plane to be 70557.61063kg, but i still don't know what I'm doing wrong to get the distance traveled down the runway.

You had a mistake in your distance equation:
D=Vit+at^2
That should be D = Vit + 0.5at^2.
 

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