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afk94
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There are two electrically charged objects that are placed 6 cm away from each other. Each object has an electrical charge of +1 microColoumbs and a mass of 1 milligram. If one object is fixed in place, how far does the other go in 2 milliseconds?
So I'm given the charge, distance between the charges, the mass of the charges, and the change in time.
1. I started by finding the Force of each charge on the other using F=k qA*qB/d^2. I got 2.5 N as my answer.
2. I then used F=ma or more specifically a=F/m to find the acceleration which I got as 2.5*10^6 N/kg.
3. I then solved for final Velocity by using Vf = Vi +at (I assumed Vi was 0) and got 5*10^3 m/s
4. I then solved for Average velocity by using Vavg = 1/2 (Vi + Vf) and got 2.5*10^3 m/s
5. I then found the distance by using d = Vavg *Δt and got 5 m.
Can anyone tell me if I got the correct answer and if I used the correct steps. If not, what did I do wrong? Thanks
So I'm given the charge, distance between the charges, the mass of the charges, and the change in time.
1. I started by finding the Force of each charge on the other using F=k qA*qB/d^2. I got 2.5 N as my answer.
2. I then used F=ma or more specifically a=F/m to find the acceleration which I got as 2.5*10^6 N/kg.
3. I then solved for final Velocity by using Vf = Vi +at (I assumed Vi was 0) and got 5*10^3 m/s
4. I then solved for Average velocity by using Vavg = 1/2 (Vi + Vf) and got 2.5*10^3 m/s
5. I then found the distance by using d = Vavg *Δt and got 5 m.
Can anyone tell me if I got the correct answer and if I used the correct steps. If not, what did I do wrong? Thanks