Calculating Acceleration for Airplane Takeoff | Simple Physics Problem

  • Thread starter Thread starter hotshot1kille
  • Start date Start date
  • Tags Tags
    Airplane
Click For Summary

Homework Help Overview

The discussion revolves around calculating the acceleration required for an airplane to take off, given a specific takeoff velocity and time on the runway. The problem is situated within the context of basic physics, particularly kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of acceleration using the formula for final velocity, questioning the accuracy of the original poster's computations. Some participants suggest that there may be an error in the interpretation of the velocity required for takeoff, proposing that the velocity should be 240 km/h instead of 2.4 km/h.

Discussion Status

There is an ongoing examination of the calculations presented, with some participants providing corrections regarding the exponent in the acceleration value. The discussion includes questioning the clarity of the problem statement and the assumptions regarding directionality in the context of the airplane's motion.

Contextual Notes

Participants note that the problem may contain unrealistic values for takeoff speed, leading to confusion about the calculations. There is also mention of the lack of clarity regarding the direction of the airplane's motion, which some consider a flaw in the question.

hotshot1kille
Messages
22
Reaction score
0

Homework Statement



A plane must reach a velocity of 2.4 km/h to lift off. If it has 45s of runway time, what must its acceleration be?

vf= 2.4km/h or 0.666666666666 m/s

vi=0.0 m/s

Δt=45s

a= ?

Homework Equations



vf= vi+ aΔt

The Attempt at a Solution

vf- vi
------- = a
Δt

0.666666666-0.0
---------------- = a
45 s

a= 0.014814814 m/s^2
a= 1.5 * 10^2 m/s^2

i did all of this but i am getting the wrong answer. Can someone tell me what i am doing wrong?
 
Physics news on Phys.org
a = 1.5 * 10^ (-2) m/s^2

negative 2 not positive 2
otherwise it seems fine
 
the answer is 1.5 * 10 ^ 2 m/s^2 [E]. but they don't state which direction is negative or positive. so i am still right?
 
Seems like two orders of magnitude error here. And that lift off speed is a very leisure walk speed. Could it be that the question reads:
A plane must reach a velocity of 240 km/h to lift off.
 
as for direction, if it didn't state which way the airplane was flying, then it doesn't matter
I would say it is a bad question

and for 10^-2

the answer should be 10^-2 not 10^2
because the answer was 0.015

think about it, 10^-2 =1/(10^2) = 1/100 =0.01
so the answer should be 1.5 x 0.01 =0.015
 
I got it directly from the worksheet i have and it says it must reach a velocity of 2.4 km/h. I know it is not realistic in a real world, but considering that the teacher just made up numbers so we can practice.
 
Andre said:
Seems like two orders of magnitude error here. And that lift off speed is a very leisure walk speed. Could it be that the question reads:
A plane must reach a velocity of 240 km/h to lift off.

yes maybe that is the problem
the airplane cannot fly when its speed is slower than a hamster on treadmill
 
arpeggio said:
as for direction, if it didn't state which way the airplane was flying, then it doesn't matter
I would say it is a bad question

and for 10^-2

the answer should be 10^-2 not 10^2
because the answer was 0.015

think about it, 10^-2 =1/(10^2) = 1/100 =0.01
so the answer should be 1.5 x 0.01 =0.015


ye i agree with you
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
10
Views
4K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K