How do you calculate the moments of inertia for a cone?

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This discussion focuses on calculating the moments of inertia for a cone, specifically addressing the integration process required to derive the moment of inertia about the z-axis. The integration involves evaluating the triple integral of the function (x+z)(x²+y²) over the volume of the cone, defined by the limits of integration for z from 0 to z₀, and for x and y based on the circular cross-section of the cone. Participants in the forum provide guidance on setting up the integral correctly to achieve the desired result.

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Kaspelek
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Hi Guys,

It has been a while since my last post but it's great to be back.

I am having some trouble with part b) of this question. Don't fully understand the concept and what I'm meant to do.

Any guidance or assistance would be greatly appreciated.

Thanks in advance you legends!
 

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Re: Regions and moments of intertia

Kaspelek said:
Hi Guys,

It has been a while since my last post but it's great to be back.

I am having some trouble with part b) of this question. Don't fully understand the concept and what I'm meant to do.

Any guidance or assistance would be greatly appreciated.

Thanks in advance you legends!

Welcome back Kaspelek! :)

Which intersection points did you find in (a)?Let's start with the cone up to some limit $z_0$.
The cone intersect with any plane with constant $z$ as a circle with radius $z$.
Such a circle can be integrated by running $x$ from $-z$ to $+z$, and by running y from $-\sqrt{z^2-x^2}$ to $+\sqrt{z^2-x^2}$.

\begin{aligned}
\iiint_{\text{Cone}} \mu (x^2+y^2)dV
&= \iiint_{\text{Cone}} (x+z) (x^2+y^2)dV \\
&= \int_0^{z_0}\int_{-z}^{+z}\int_{-\sqrt{z^2-x^2}}^{+\sqrt{z^2-x^2}} (x+z) (x^2+y^2) dydxdz
\end{aligned}
Do you know how to calculate that?
 

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