How Do You Calculate the Normal Vector of a Sphere in Spherical Coordinates?

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SUMMARY

The discussion focuses on calculating the normal vector of a sphere defined by the equation V = x² + y² + z² ≤ 1 in spherical coordinates. The conversion to spherical coordinates is correctly established as x = r sin(t) cos(f), y = r sin(t) sin(f), and z = r cos(t), with t ranging from 0 to π and f from 0 to 2π. To find the normal vector, participants suggest using the gradient ∇f of the surface, which is applicable in both Cartesian and spherical coordinates. The conversation also touches on the application of the divergence theorem of Gauss in this context.

PREREQUISITES
  • Understanding of spherical coordinates and their conversion from Cartesian coordinates.
  • Knowledge of vector calculus, specifically the gradient operator ∇.
  • Familiarity with the divergence theorem of Gauss.
  • Basic proficiency in mathematical notation and surface equations.
NEXT STEPS
  • Study the calculation of gradients in spherical coordinates.
  • Research the divergence theorem of Gauss and its applications in vector fields.
  • Explore examples of normal vector calculations for various surfaces.
  • Learn about the implications of normal vectors in physics, particularly in fluid dynamics.
USEFUL FOR

Mathematicians, physics students, and anyone involved in vector calculus or surface analysis will benefit from this discussion, particularly those interested in applying the divergence theorem and calculating normal vectors in spherical coordinates.

brunette15
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I am given the sphere V= x^2 + y^2 + z^2 =< 1

I have converted it to spherical coordinates:

x = rsin(t)cos(f)
y = rsin(t)cos(f)
z = rcos(t)

where t ranges from 0 to pi, and f ranges from 0 to 2pi.

I am unsure how to go about this problem from here. Any guidance would be really appreciated :)
 
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brunette15 said:
I am given the sphere V= x^2 + y^2 + z^2 =< 1

I have converted it to spherical coordinates:

x = rsin(t)cos(f)
y = rsin(t)cos(f)
z = rcos(t)

where t ranges from 0 to pi, and f ranges from 0 to 2pi.

I am unsure how to go about this problem from here. Any guidance would be really appreciated :)

Hey brunette15! ;)

We can find the normal of a surface $f(x,y,z)=0$ by taking the gradient $\nabla f$... (Thinking)
 
I like Serena said:
Hey brunette15! ;)

We can find the normal of a surface $f(x,y,z)=0$ by taking the gradient $\nabla f$... (Thinking)

Hi again I like Serena :)

I am aware that we could do that but for this particular case i am trying to prove the divergence theorem of Gauss :/
 
brunette15 said:
Hi again I like Serena :)

I am aware that we could do that but for this particular case i am trying to prove the divergence theorem of Gauss :/

Huh? :confused:

What do you want to do then?

Do you want to find the normal in polar coordinates?
If so, the method is the same - we just need the gradient in polar coordinates instead of cartesian coordinates.
 

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