How Do You Calculate the Percent by Weight of Sodium in Na2S2O3?

AI Thread Summary
To calculate the percent by weight of sodium in Na2S2O3, first determine the total mass of the compound by accounting for the number of each element: two sodium (Na), two sulfur (S), and three oxygen (O) atoms. The atomic masses are 23 g for Na, 32 g for S, and 16 g for O. The total mass of Na2S2O3 is calculated as (2*23) + (2*32) + (3*16), which equals 158 grams. The mass contribution from sodium is 46 grams (2*23). This results in sodium making up approximately 29% of the total mass of the compound.
Richay
Messages
39
Reaction score
0
How on Earth do you do this?

What percent by weight of Na2S2O3 is Sodium (Na)? (Na, 23; S, 32; 0, 16)

Okay that looks confusing but. The "Na2S2O3" isn't suppose to be spelled like that. It's Na (then a 2 that is haflway beneath the number) And then you repeat with S (lower 2), O and lower 3. It's hard to explaina and i don't know what it's called.

But how do i solve this?
 
Physics news on Phys.org
I take it that the text in parentheses refers to the masses of each of the elements in the compound.

A good start would be to calculate the total mass of the compound, keeping in mind the fact that there are different numbers of each element in the compound (i.e. there are 2 sodium ions, etc.).
 
How do i calculate it though? I don't understand the 2,2,&3 that belong to Na,S,&O
 
Na2S2O3 means that the given molecule/unit (Sodium thiosulfate) is composed of two atoms of Na, two atoms of S, and three atoms of O.

By looking at a periodic table (or the values that are given to you) you can realize that one mole of Na has a mass of 23 grams. One mole of S has a mass of 32 grams. One mole of O has a mass of 16 grams.
 
Last edited:
Thanks.
I figured out it's 29%
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top