How Do You Calculate the Rotation Rate of a Space Station Wheel?

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Homework Help Overview

The problem involves calculating the rotation rate of a space station designed as a wheel with a diameter of 120m, intended to create an artificial gravity of 3.00 m/s². The required output is in revolutions per minute (rev/min).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the centripetal acceleration formula ac = v²/r and explore the relationship between linear velocity and angular velocity. There is mention of using the circumference of the wheel for calculations and a conversion factor involving 2π.

Discussion Status

Some participants have attempted recalculating their answers after considering the circumference and the conversion factor. There is a recognition of differing results, with one participant noting a closer approximation to the expected answer but still not matching it. Clarification on the meaning of angular velocity (ω) is also being sought.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available or the methods they can use. There is an acknowledgment of the need for correct application of formulas and conversion factors.

Ninjaku
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Homework Statement



Basically the problem is asking me to find the rate of rotation of a space station that is in the shape of a wheel 120m in diameter, and rotates to provide an "artificial gravity" of 3.00 m/s.

And it has to be in rev/min.


Homework Equations



The only equation so far I that has to deal with this is the one

ac = v^2/r

The Attempt at a Solution



it seemed pretty simple and straightforward. So first i took the gravity which is of course the acceleration in this case. And then set it equal to v^2/60.

Then i solved for v.

After solving for v I used that to see how long one revolution is by using the equation, v=d/t. Substituting in the 120 m for d.

So I send up with a time in sec for every 120m revolution.
Then I converted from sec to min by divinding by 60.

I still can't get the answer in the book.
 
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Hi Ninjaku! :smile:

(have an omega: ω and a pi: π and try using the X2 tag just above the Reply box :wink:)
Ninjaku said:
So I send up with a time in sec for every 120m revolution.
Then I converted from sec to min by divinding by 60.

I still can't get the answer in the book.

Did you use the 2π factor to convert radius to circumference? :wink:

(and btw it would have been easier to start with the alternative formula ac = ω2r instead of v2/r)
 
Hey thanks for the reply.

I retried the the computation with the 2π conversion factor that I forgot on my first try. And my answer is a little closer but still no cigar.

The answer in the book is 2.14rev/min

I got .084388.

Oh and I'm not reallly familiar with that other formula, what does omega represent in that equation.
 
Well, I make it 2.14 also.

Show us how you got .084388.

(ω is the angular velocity in radians per second: v = ωr, ω = v/r :wink:)
 

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