How Do You Calculate the Specific Latent Heat of Fusion of Nitrogen?

Click For Summary
SUMMARY

The discussion focuses on calculating the specific latent heat of fusion of nitrogen, which melts at 63 K. The specific heat capacity of solid nitrogen is established as 1.6 kJ kg-1 K-1. Participants analyze a temperature vs. time graph to determine the rate of heat absorption before melting and use this information to calculate the heat required for the phase change from solid to liquid. The calculations involve using the heating rate derived from the specific heat capacity and the temperature rise over a specified time period.

PREREQUISITES
  • Understanding of specific heat capacity and latent heat concepts
  • Familiarity with temperature vs. time graph interpretation
  • Basic knowledge of thermodynamics principles
  • Ability to perform calculations involving heat transfer
NEXT STEPS
  • Calculate the specific latent heat of fusion for nitrogen using the derived heating rate
  • Learn about the specific heat capacity of liquid nitrogen
  • Explore phase change thermodynamics in detail
  • Investigate the properties of nitrogen at various temperatures and pressures
USEFUL FOR

Students studying thermodynamics, physics educators, and researchers interested in cryogenics and the properties of nitrogen.

henry ballantyne
Messages
1
Reaction score
0

Homework Statement


The graph below shows the result of an investigation in which an initially solid specimen of nitrogen absorbs heat a constant rate. Nitrogen melts at 63 K and the specific heat capacity of solid nitrogen is 1.6 kJ kg^-1 K^-1.

attachment.php?attachmentid=508719&d=1456706123&thumb=1.png

Homework Equations


shc od solid nitrogen = 1.6 kJ kg^-1 K^-1.
a) Calculate the specific latent heat of fusion of nitrogen.
b) Calculate the specific heat capacity for liquid nitrogen

The Attempt at a Solution



I'm guessing that the temp vs time graph will give me the rate at which heat is being absorbed in the stage before melting by giving you the temperature rise per second.
Assuming heat is being absorbed at the same rate during the change from solid to liquid, I know, from the time on the graph, how much heat was needed to melt it.
I've worked that much out but don't where to go from there.
 
Physics news on Phys.org
You can get the heating rate from the 1.6 kJ/kg-K in conjunction with the 10 degree rise for the solid in 160 sec. (Assume 1 kg).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
798
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 1 ·
Replies
1
Views
1K