How Do You Calculate the Total Moment of Forces on a Plane?

  • Thread starter Thread starter go2255
  • Start date Start date
  • Tags Tags
    Moment
Click For Summary
SUMMARY

The total moment of forces on a plane can be calculated using the formula (r - r(a)) x F, where r represents the point of application of the force and r(a) is the reference point about which moments are calculated. In the given example, with forces F(1) = i - 2j + k and F(2) = 3i + 3j + 2k acting through points P and Q respectively, the total moment about point R is determined by the vector sum of the individual moments: (OP - OR) x F(1) + (OQ - OR) x F(2). This method accurately computes the total moment when multiple forces act at different points.

PREREQUISITES
  • Understanding of vector mathematics
  • Familiarity with cross product operations
  • Knowledge of force vectors and their applications
  • Basic principles of static equilibrium in mechanics
NEXT STEPS
  • Study vector cross product properties in physics
  • Learn about static equilibrium and moment calculations in mechanics
  • Explore applications of forces in three-dimensional space
  • Investigate advanced topics in mechanics, such as torque and angular momentum
USEFUL FOR

Students and professionals in physics, engineering, and mechanics who are involved in analyzing forces and moments in static systems, particularly those working with three-dimensional structures.

go2255
Messages
11
Reaction score
0
I heard that the moment of F about point a is (r-r(a))xF
but i can't understand what r and r(a) are.And when there are 2 forces act though different point,how can I find the total moment.

e.g:
Four points:O(0,0,0) P(9,-3,5) Q(6,4,7) R(3,2,3.5).
OPQ is a triangular plane and R is a point on this plane.
Two forces, F(1)=i-2j+k and F(2)=3i+3j+2k act through the points P and Q respectively.
If the triangle OPQ is fixed at the point R, what is the total moment of the two forces about it??

I do it like that:(OP-OR)xF(1)+(OQ-OR)xF(2)
Is that right?
 
Physics news on Phys.org
hi go2255! welcome to pf! :smile:
go2255 said:
I heard that the moment of F about point a is (r-r(a))xF
but i can't understand what r and r(a) are

r is the point of application of the force (or any point on the line of application)

r(a) is the point about which you're taking the moments

in fact, you've got it correct in your example :wink:
I do it like that:(OP-OR)xF(1)+(OQ-OR)xF(2)
Is that right?
.And when there are 2 forces act though different point,how can I find the total moment.

you add the two moments (as vectors)
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 42 ·
2
Replies
42
Views
4K
Replies
3
Views
1K
Replies
4
Views
1K
Replies
335
Views
16K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K