How Do You Calculate Thevenin Equivalent Circuit Without a Load Resistor?

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SUMMARY

The discussion focuses on calculating the Thevenin equivalent circuit without a load resistor, specifically across terminals a and b. Key steps include removing the load resistor, finding the open circuit voltage, and determining the equivalent circuit resistance by suppressing independent sources. The correct approach to handling current sources is emphasized, requiring them to be removed entirely rather than short-circuited. The final calculated values include a total resistance of 0.75 ohms and an open circuit voltage of -10.667 volts.

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  • Understanding of Thevenin's theorem
  • Familiarity with circuit analysis techniques
  • Knowledge of voltage and current sources
  • Ability to calculate equivalent resistance in parallel circuits
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Alexander Max
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Homework Statement


upload_2015-1-5_22-42-49.png

I am to find the thevenin equivalent circuit without the load resistor (to the left of terminals a &b

Homework Equations



From class notes:
1- Remove the load resistor
2- find the open circuit voltage across a & b
3- Remove all voltage sources (replace with short circuit)
4- Detrmine the equivalent circuit resistance across the break
5- Form an equivalent circuit

The Attempt at a Solution



I have not come across the symbol that looks like an 8 with the 2amps next to it so far, and i don't understand how this will effect my circuit, is it a voltage source, how will it effect the resistors?
Without acknowledging it,
my resistors are all in parralel so Restance total is
1/RT = 1/R1 + 1/R2 + 1/R3
1/RT = 1/4 + 1/12 + 1/1
1/RT = 3/12 + 1/12 + 12/12
1/RT = 16/12
RT = 12/16
RT = 0.75

32v/0.75 ohms = 42.667 Amps
Vab = 32 - 1x42.667Amps = -10.667 Volts

Resistance looking in has already been calulated as 0.75 ohms

 

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Hello Alex, and welcome to PF :)

The 2A thingy is a (slightly outdated) symbol for a current source.

I don't see how you can consider all R as parallel.
 
Hi Alexander Max, Welcome to Physics Forums.

As BvU stated, the two-circle symbol represents a current source. It's a bit outmoded as a schematic symbol, but it still crops up fairly often.

Allow me to amend your algorithm's item 3 a bit, since in its given form it doesn't address current sources:

3 - Suppress all independent sources: Replace voltage sources with a short circuit and all current sources with an open circuit (simply remove them entirely).
 
Thank you for your help!
 

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