- #1
oddjobmj
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Homework Statement
http://imgur.com/w5AQ1A8
As shown in the image:
In the circuit below R1=100Ω, R2=1000Ω, R3=99Ω, R4=1000Ω, R5=10Ω, and V=10V.
(a) Relying on the Thevenin theorem, find the equivalent voltage and equivalent resistance for the circuit below when the resistor R5 is taken out.
(b) What is the current through R5 when it is put back into the circuit?
(c) If R5=10kΩ were put in instead of 10Ω, what would be the current through it?
(d) Calculate the voltage across R5 for the conditions in (b) and (c), respectively.
Homework Equations
V=IR
Parallel Resistors=[itex]\frac{1}{\frac{1}{R_a}+\frac{1}{R_b}}[/itex]
Series Resistors=Ra+Rb
The Attempt at a Solution
I am having a hard time with Thevenin equivalent circuits. The problem doesn't seem to make it clear where my terminals should be. If all I have to do is find the equivalent resistor of R1 and R3 in series, R2 and R4 in series, and those equivalent resistors in parallel then part (a) should be simple. I'm not sure if it matters where the terminals are.
If that is the case I get RTH≈181Ω and VTH would just be V=30V.
For part (b) I have to start over it seems. I have no idea how to do this without resorting to other methods such as meshes. I have a feeling I can simplify this circuit in a useful way using Thevenin's theorem but how I do that and still know where R5 comes in I don't know.
Suggestions? Thank you for your help.
EDIT: I was able to plug this into multism to find the answers to (b), (c), and (d) so I can check my work. I do need to understand this and also show my work though.
(b) 45.296 μA
(c) 45.296 μA (same?)
(d) V10=448.873 μV, V10k=23.816 mV
EDIT 2:
Hah! Just realized how badly I botched the title. *facepalm*
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