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apoptosis

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## Homework Statement

There is a solid lying between planes perpendicular to the x-axis from x= -[tex]\pi[/tex]/3 to [tex]\pi[/tex]/3. Cross sections on the x-axis are perpendicular to the x-axis are circular disks where the diameter goes from the curve y=tanx to y=secx. Find the volume (by slicing).

## Homework Equations

All righty. So far I have graphed the two curves from the two x endpoints.

since y=secx is above y=tanx

L=f(x)=secx-tanx

A(x)=([tex]\pi[/tex]D^2)/4

Therefore A(x)=([tex]\pi[/tex](secx-tanx)^2)/4

For volume:

I have the integral from [tex]\pi[/tex]/3 to -[tex]\pi[/tex]/3 A(x)

## The Attempt at a Solution

For the solutionn, I know that I have to find the antiderivative of A(x) and take the difference from the two endpoints. Which the the step that I'm stuck at if I have done everything else correct.

Could I have missed a step, or actually am off track with this problem?

Thanks!