How Do You Calculate Yield Stress in an Aluminium Single Crystal Alloy?

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SUMMARY

The calculation of yield stress in an aluminium single crystal alloy involves applying Schmid's law, particularly when the tensile stress is oriented along a [102] direction and slip occurs on a (111) plane with a valid slip direction. The critical resolved shear stress for this scenario is given as 3.42 MPa. It is essential to correctly identify the slip direction, as the [101] direction is invalid for the (111) plane. Utilizing the dot product to determine cosφ and cosλ from the vectors representing the load and slip directions is crucial for accurate yield stress computation.

PREREQUISITES
  • Understanding of Schmid's law in materials science
  • Familiarity with crystallography, specifically cubic crystal structures
  • Knowledge of vector mathematics, particularly dot products
  • Experience with calculating resolved shear stress in single crystal materials
NEXT STEPS
  • Study the application of Schmid's law in different crystal orientations
  • Learn about the mechanics of slip in single crystal alloys
  • Explore vector mathematics and its applications in materials science
  • Investigate the properties of aluminium alloys and their yield stress characteristics
USEFUL FOR

Materials scientists, mechanical engineers, and students studying crystallography or materials mechanics will benefit from this discussion, particularly those focused on yield stress calculations in single crystal alloys.

edcurrymuncher
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Hey, this was the question could someone please help?

"An aluminium single crystal alloy aircraft component is oriented such that a tensile stress is applied along a [102] direction. If slip in this material occurs on a (111) plane
and in a [101] direction, compute the yield stress at which the crystal yields if its critical resolved shear stress is 3.42MPa."

Thanks :)
 
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Suggest you do your own Schmid's law homework.

PS the [101] direction isn't a valid direction in the (111) plane.
 
I am no authority on the subject but I recently did a problem very similar to the one you're working on. And I believe the poster above me is correct in their assertion. In my problem, the applied load was [120], slip plane (111) and slip direction [110].

Something helpful (which I learned from my professors) is to draw the cubic cell with the indicated plane and directions. This will help you get a feel of what \phi and \lambda look like. In addition to load and slip directions, you will also need to determine the direction perpendicular to the slip plane.

The key, however, is to use the dot product to find cos\phi and cos\lambda. In order to do this you will need to treat the three key directions as vectors.

Hopefully this was of some help to you.
 

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