How do you derive this (E=v/d)?

  • Thread starter dE_logics
  • Start date
  • #1
741
0
How do you derive this (E=v/d)?
 

Answers and Replies

  • #3
741
0


aaaaa :biggrin: that sorta went over my head.

Can you do it with this relation -

V = k(q/d)

i.e potential difference at a distance d from a charged particle q of a unit charge brought from infinity.
 
  • #4
741
0


There's something wrong with latex...its showing my old codes.
 
  • #5
741
0


Yep got that --

In V = k(q/d) substitute q with (Ed2)/k (derived from E.F at a point from a source charge q)

Solve and you get it.
 

Related Threads on How do you derive this (E=v/d)?

  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
5
Views
8K
Replies
3
Views
104K
  • Last Post
  • Optics
Replies
1
Views
870
Replies
29
Views
20K
Replies
2
Views
2K
  • Last Post
Replies
3
Views
4K
Replies
2
Views
3K
Replies
1
Views
1K
Replies
1
Views
3K
Top