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How do you derive this (E=v/d)?

  1. Apr 26, 2009 #1

    dE_logics

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    How do you derive this (E=v/d)?
     
    dE_logics, Apr 26, 2009
  2. jcsd
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  3. Apr 26, 2009 #2

    Feldoh

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    Feldoh, Apr 26, 2009
  4. Apr 26, 2009 #3

    dE_logics

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    Re: E=V/d

    aaaaa :biggrin: that sorta went over my head.

    Can you do it with this relation -

    V = k(q/d)

    i.e potential difference at a distance d from a charged particle q of a unit charge brought from infinity.
     
    dE_logics, Apr 26, 2009
  5. Apr 26, 2009 #4

    dE_logics

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    Re: E=V/d

    There's something wrong with latex...its showing my old codes.
     
    dE_logics, Apr 26, 2009
  6. Apr 26, 2009 #5

    dE_logics

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    Re: E=V/d

    Yep got that --

    In V = k(q/d) substitute q with (Ed2)/k (derived from E.F at a point from a source charge q)

    Solve and you get it.
     
    dE_logics, Apr 26, 2009
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