How do you derive this (E=v/d)?

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The discussion focuses on deriving the equation E = v/d from the relationship between electric potential and the electric field. It begins with the understanding that electric potential is the negative line integral of the electric field when both are aligned. Participants suggest using the formula V = k(q/d) for potential difference and substituting q with (Ed²)/k, which is derived from the electric field at a point from a source charge. By solving this substitution, the relation E = v/d is confirmed. The conversation highlights the connection between electric potential, electric field, and distance in electrostatics.
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How do you derive this (E=v/d)?
 
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aaaaa :biggrin: that sort of went over my head.

Can you do it with this relation -

V = k(q/d)

i.e potential difference at a distance d from a charged particle q of a unit charge brought from infinity.
 


There's something wrong with latex...its showing my old codes.
 


Yep got that --

In V = k(q/d) substitute q with (Ed2)/k (derived from E.F at a point from a source charge q)

Solve and you get it.
 
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