The discussion revolves around determining Superman's initial velocity in a two-dimensional momentum problem involving Lois Lane's fall. Participants are exploring the implications of momentum and kinematics in the context of the scenario presented.
There is ongoing exploration of various approaches to the problem, with some participants offering guidance on using known variables like acceleration due to gravity. Others are attempting to clarify their understanding of the momentum equations and the necessary calculations to find the required velocities.
Participants note the absence of specific speed values for the characters involved, which complicates the calculations. There is also mention of the need to adhere to homework rules regarding the sharing of complete solutions.
How far will Lois have fallen when she is caught?Walter White said:
It has to be the difference between the 2 heights. 13.2 - 6.8.haruspex said:
So what is Lois' velocity when they meet?Walter White said:
When you say you need time, do you mean you think you need to know how much time elapsed, or merely that you cannot work it out immediately?Walter White said:
Like I need the time to figure out the velocity from the formula d/tharuspex said:
Yes how much time was elapsed because there's no mention of time in the problemharuspex said:
For motion under constant acceleration, there are five standard variables (usually known as SUVAT, s for displacement, u for initial speed, v for final speed, a for acceleration, t for time). There are correspondingly five equations. Each equation omits one of the five variables. Are you familiar with these?Walter White said:
Right. I suggest you Google SUVAT. Plenty of references. Or, in this case, you can use work conservation.Walter White said:
Stick with vertical motion for now. You know the vertical speed of each just before they meet. Can you find their vertical speed just afterwards?Walter White said:
Please post your working.Walter White said:
First I found Louiss velocity using this formula in the above imageWalter White said:
I cannot follow what you did there, not only because it was upside down and hard to read. (The posting of images is intended for diagrams and textbook extracts. Please take the trouble to type in your working. This makes it both easier to read and easier to make specific comments on.)Walter White said:
No, Superman's initial velocity is what you have to find. I see no 9.8m/s in the question statement.Walter White said:
