How do you do a Lewis Diagram for a charged molecule?

[jumbogala]

Homework Statement

Draw the Lewis Diagram for XeF₂?

Homework Equations

The Attempt at a Solution

EDIT: Maybe this isn't a charged molecule...

How can 2 fluorines bond with Xe? Xe has no valence electrons to bond with! I guess you could do

F-Xe-F, but still, the fluorines have nowhere to bond...

 

[Epsillon]

Xe does not obey the octet rule. It has 10
..
:F:
|
:Xe::
|
:F:

 

[Blueshift5]

I would like to clarify that XeF2 is not a charged molecule. It is a neutral molecule, meaning it has an equal number of protons and electrons. Therefore, a Lewis diagram for XeF2 would be drawn as follows:

Xe (with 8 dots around it) - F (with 6 dots around it) - F (with 6 dots around it)

This diagram shows the two fluorine atoms bonding with the xenon atom by sharing a pair of electrons, resulting in a stable molecule. The octet rule is satisfied for both the xenon and fluorine atoms, with each having a full outer shell of electrons.

If the molecule were to become charged, for example, by losing or gaining an electron, the Lewis diagram would be modified accordingly. For a positively charged XeF2 molecule (XeF2+), one electron would be removed from the overall structure, resulting in a Lewis diagram with one fewer electron around the xenon atom. Conversely, for a negatively charged XeF2 molecule (XeF2-), an extra electron would be added to the overall structure, resulting in a Lewis diagram with one additional electron around the xenon atom.

In summary, the Lewis diagram for a charged molecule would involve modifying the number of electrons around the central atom to reflect the overall charge of the molecule.