How Do You Evaluate the Integral of e^x from 0 to 3 ln2?

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SUMMARY

The integral of e^x from 0 to 3 ln2 is evaluated using the fundamental theorem of calculus. The integral is calculated as ∫ e^x dx = e^x, leading to the evaluation at the limits: e^(3 ln2) - e^0. Simplifying e^(3 ln2) results in e^(ln8), which equals 8. Therefore, the final result of the integral is 8 - 1, yielding a total of 7.

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Homework Statement



Evaluate

∫ e^x dx

upper limit: 3 ln2
lower limit: 0



Homework Equations





The Attempt at a Solution




I'm not sure if I'm doing this right;

the integral of e^x = e^x

now with the lmits

[e^3ln2 - e^0]

?

lol thanks
 
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yup. now all you need to do is just simplify with your natural log and exponential rules.
 
I understand it now.

e^3ln2 = e^ln8 = 8

e^0 = 1

8-1 = 7Thanks
 

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