How Do You Find <r^2> for Uncertainty in Position?

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Homework Help Overview

The discussion revolves around calculating the uncertainty in position, specifically focusing on finding the expectation values and ^2 in the context of quantum mechanics, particularly for the ground state of hydrogen.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method for calculating , with one suggesting the integration of r^2 p(r) dr. Questions arise regarding the evaluation of integrals and the use of integration tables.

Discussion Status

Some participants have provided guidance on the integration process, while others express uncertainty about specific details, such as the integral used and the parameter 'a'. There is a mix of confirmed calculations and requests for clarification on the results obtained.

Contextual Notes

There is mention of a table for integrals and concerns about the size of the uncertainty value calculated, indicating a potential need for further exploration of the assumptions or parameters involved.

swain1
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When trying to work out the uncerainty in position of the expectation value I have read that you have to find <r^2> as well as <r>^2. I have worked out the value of 3a/2 for <r> but what do I have to do to find <r^2>. Do I just sqare the whole function before I integrate?
Also as I am integrating I found, in a book a table that had a general form of integrations between 0 and infinity. I used it without giving it much thought but how would you evaluate this? Thanks:confused:
 
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Yes to find <r^2> you integrate r^2 p(r) dr instead of rp(r)dr. Or for any function of r, it's just int[f(r)p(r)dr].

I'm guessing the table was for the gaussian interal int[exp(-ax^2)] a>0? The integral can't be evaluated directly, you have to do some weird substitutions, if you want to know how to do it I can show you. It's easiest to remember the the soln is sqrt(pi/a), from 0 to infinity is half this, and for x^2n exp(-ax^2), differentiate both sides wrt a.
 
Ok thanks for that. I have done the inegral and worked out the uncertainty. The value I have got is sqrt(3)a/2. It seems like an awful lot to me. Anyway, do you know if this is right. I am doing this for the ground state of hydrogen. If I have got the correct value. Why is it so large?
 
Not entirely sure, what exactly was the integral? And what is a? I haven't done any quantum, not sure what this is about exactly.
 
[tex]\Delta r = \sqrt{<r^2> - <r>^2}[/tex]
 

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