How do you find the determinant of a 3x3 matrix with polynomial equations?

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SUMMARY

The discussion focuses on finding the determinant of a 3x3 matrix containing polynomial equations. Participants confirm that the standard determinant formula for a numerical matrix applies, despite the presence of polynomial entries. The presence of two zeros in the third column simplifies the calculation, allowing for cofactor expansion. The correct approach involves using the determinant formula a11(a22*a33 - a32*a23) and can also utilize the cofactor expansion method on any column or row.

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  • Understanding of 3x3 matrix determinants
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  • Knowledge of cofactor expansion and minors
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snoggerT
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M= |3-2x^3_____-4+2x^2+4x^3______0|
|-x^3________1+x^2+2x^3_______0|
|-8-6x^2_____16+12x^2____-1-3x^2|

find the determinant.

* I put the underscores for spacing.

The Attempt at a Solution



I first tried finding det(A) as if it was a regular matrix of numbers, but that doesn't seem to work. So I'm really not sure how to find the determinant for a matrix of polynomial equations. Where would you actually start?
 
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Well, one can use the fact that the third column has two zeros as entries.

Think about

+ - +
- + -
+ - +
 
I'm not quite getting what I'm supposed to see from the 2 zeros. The way I worked it out before was using the normal determinant method of a11(a22*a33-a32*a23)-a12...etc. Would that not be the correct way to find a determinant for this type of matrix?
 
snoggerT said:
M= |3-2x^3_____-4+2x^2+4x^3______0|
|-x^3________1+x^2+2x^3_______0|
|-8-6x^2_____16+12x^2____-1-3x^2|

find the determinant.

* I put the underscores for spacing.






The Attempt at a Solution



I first tried finding det(A) as if it was a regular matrix of numbers, but that doesn't seem to work. So I'm really not sure how to find the determinant for a matrix of polynomial equations. Where would you actually start?

It should work! If it does not work, check your calculation. It's really the same as the determinant of a matrix of numbers. The fact that there are two zeroes will make the final result not too awful looking. But it's the usual formula for the determinant of a 3 by 3 matrix.

EDIT: give your answer (before expanded out) and we can check if you made a mistake
 
Last edited:
snoggerT said:
I'm not quite getting what I'm supposed to see from the 2 zeros. The way I worked it out before was using the normal determinant method of a11(a22*a33-a32*a23)-a12...etc. Would that not be the correct way to find a determinant for this type of matrix?
That would be one way. The co-factor expansion (or determinant expansion by minors) can be done on any column or row! If one does is using the third column, one sees a33|A33|, where A33 is the 3,3 minor.

http://mathworld.wolfram.com/DeterminantExpansionbyMinors.html

See the examples here - http://en.wikipedia.org/wiki/Laplace_expansion - using first row or second column. One can also use the third row or third column.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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