How do you find the normal component of a function F (Stoke's theorem question)

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SUMMARY

The discussion centers on finding the normal component of a vector-valued function F along a surface S in the context of Stokes' theorem. Stokes' theorem states that the line integral of F along a curve is equal to the surface integral of the curl of F dotted with the unit normal vector n over the surface bounded by the curve. The normal vector n is defined as the unit vector normal to the surface, which can typically be determined easily for most surfaces.

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theneedtoknow
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Homework Statement


This isn't really regarding any specific question, I am just wondering how do I find the normal component of a vector valued function along a surface S?

Stoke's theorem says the integral over a curve of F (dot) dx is equal to the integral of curlF (dot) n dA over the surface bound by the curve. If I have a function F (you can make one up if it helps explain) to integrate over a surface , how do I find the normal component "n" that I need to use?

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The Attempt at a Solution

 
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theneedtoknow said:
Stoke's theorem says the integral over a curve of F (dot) dx is equal to the integral of curlF (dot) n dA over the surface bound by the curve. If I have a function F (you can make one up if it helps explain) to integrate over a surface , how do I find the normal component "n" that I need to use?

Hi theneedtoknow! :smile:

n isn't the normal component, it's the unit vector normal to the surface. :wink:

For most surfaces, that should be fairly easy to find. :smile:
 

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