How Do You Integrate (2x^2+1)/x?

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SUMMARY

The integral of the function (2x^2 + 1)/x can be accurately decomposed into two separate integrals: ∫2x dx and ∫(1/x) dx. This results in the expression ∫(2x^2 + 1)/x dx = ∫2x dx + ∫(1/x) dx. The confusion regarding the potential for subtraction is unfounded, as the correct operation is summation, not subtraction.

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Homework Statement



I haven't done much math for years.

just a little reminder would be very appreciated.

when you take integral for (2x^2+1)/x dx

I believe this can break down into integral 2x dx + integral 1/x dx

What I wondered about was is this summation of those two as written above

or the subtraction (integral 2x dx - integral 1/x dx)

thanks.

Homework Equations





The Attempt at a Solution

 
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You have it right. The integral can be split into two integrals like you have.
 
\frac{2x^2+ 1}{x}= \frac{2x^2}{x}+ \frac{1}{x}= 2x+ \frac{1}{x}

Why would you even consider changing the "+" to "-"?
 

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