How Do You Integrate 3t^2(1+t^3)^4?

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Homework Help Overview

The problem involves integrating the expression ∫ 3t²(1 + t³)⁴ dt, which falls under the subject area of calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for integration, including integration by parts and substitution. Some express uncertainty about the appropriate technique, while others suggest that a simpler substitution might be effective.

Discussion Status

The discussion is active, with participants exploring different approaches to the integration problem. Some have indicated that they can now solve the problem, while others are still questioning the best method to use.

Contextual Notes

There is a mention of potential confusion regarding the integration rules and whether a combination of techniques is necessary. Participants are also considering the implications of the derivative of the term "1 + t³" in their approaches.

unique_pavadrin
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Homework Statement


Integrate the following:
[tex] \int {3t^2 \left( {1 + t^3 } \right)^4 \,\,dt} [/tex]


Homework Equations


[tex] \begin{array}{l}<br /> \int {\left( {a + bx} \right)^n \,\,dx = \frac{{\left( {a + bx} \right)^{n + 1} }}{{a\left( {n + 1} \right)}} + c} \\ <br /> \int {x^n \,\,dx = \frac{{x^{n + 1} }}{{n + 1}} + c} \\ <br /> \end{array}[/tex]


The Attempt at a Solution


I am unsure on how to integrate problems such as these. Is there another rule? or is it a combination of rules? Many thanks to all help provided,
unique_pavadrin
 
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One way would be to integrate by parts a few times. There's probably a quicker way that someone else may spot though.
 
how would i integrate by parts in there situations? thanks\
 
No need for integration by parts. Look at the "1 + t^3" term. What is it's derivative. This problem can be solve by a simple substitution. Do you see it?
 
TheoMcCloskey said:
No need for integration by parts. Look at the "1 + t^3" term. What is it's derivative. This problem can be solve by a simple substitution. Do you see it?

Haha, nice.. I knew there would be a quicker way!
 
okay i can solve the problem now, thanks all
 
Longer than a substitution, but shorter than integration by parts a few times, would be the expansion of the factorized expression and integrate term by term.
 

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