How Do You Integrate sec^6(t)?

[afcwestwarrior]

Homework Statement

∫sec^6 t

Homework Equations

sec^2 (x)=1+tan^2 (x)

The Attempt at a Solution

∫ (sec^2 (t))^2 * (Sec^2 (t))^2

∫(1+tan^2 (x))^2 (1+tan^2 (x))

∫(1+2tan^2 (x) +tan^4 (x)) (1+tan^2 (x))
u=tan (x) du=sec^2 dx

i'm stuck now

 

[rock.freak667]

Homework Statement

∫sec^6 t dt

Always remeber to put what you integrating with respect to.

I'll help you out a bit

$$\int sec^6(t) dt= \int sec^4(t)*sec^2(t) dt$$

Now use sec²=1+tan² to find what sec⁴will be.