How do you know if pf (power factor) is leading or lagging

  • Thread starter Thread starter pokie_panda
  • Start date Start date
  • Tags Tags
    Power factor
Click For Summary
SUMMARY

The discussion focuses on determining whether the power factor (pf) is leading or lagging based on the given voltage and current waveforms: v(t)=3.5cos(600t-120) and i(t)=2.3sin(600t+45). The calculated power factor is pf=cos(-75), which equals approximately 0.2588. To ascertain whether the current leads or lags, one must analyze the phase angles and utilize a phasor diagram. The voltage leads the current if the phase angle of the voltage (ψ1) is greater than that of the current (ψ2).

PREREQUISITES
  • Understanding of phasor diagrams and their application in AC circuits
  • Knowledge of trigonometric identities, specifically sin and cos transformations
  • Familiarity with power factor calculations in electrical engineering
  • Basic concepts of alternating current (AC) waveforms and their phase relationships
NEXT STEPS
  • Study phasor diagram construction and interpretation in AC analysis
  • Learn about the implications of leading vs. lagging power factors in electrical systems
  • Explore the use of complex numbers in AC circuit analysis
  • Investigate the effects of power factor correction techniques on system efficiency
USEFUL FOR

Electrical engineering students, professionals analyzing AC circuits, and anyone interested in understanding power factor implications in electrical systems.

pokie_panda
Messages
35
Reaction score
0

Homework Statement



power factor leading or lagging

v(t)=3.5cos(600t-120)
i(t)=2.3sin(600t+45)

Homework Equations



pf=cos(Vθ-Iθ)


The Attempt at a Solution



pf=cos(-75)
=.25881905

I get confused, How do we figure out whether it leads or lags.
 
Physics news on Phys.org
pokie_panda said:
I get confused, How do we figure out whether it leads or lags.
You draw the phasor diagram. :smile:

The phasors rotate counter-clockwise. Consider a pair rotating together, and differing by an angle ≤ 90°. Whichever passes over an axis first is the leading phasor of that pair.
 
First, change the cos voltage to a sin function. Use sin(x) = cos(x - 90 deg).
Then, you get V = sin(wt + ψ1) and i = sin(wt + ψ2).

V leads i if ψ1 > ψ2 or ψ1 - ψ2 > 0.
 
Last edited:

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K