How do you prove the partial derivative identity with three variables?

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To prove the identity (dx/dy)(dy/dz)(dz/dx) = -1 for the function f(x,y,z) = 0, one must differentiate the implicit function with respect to each variable while considering the dependencies among them. Starting with the relationships x = x(y,z), y = y(z,x), and z = z(x,y), the chain rule is applied to express the derivatives. The differentiation leads to the equation df/dx + df/dz(dz/dx) = 0, which helps establish the necessary relationships between the derivatives. Ultimately, the proof hinges on manipulating these derivatives to show their product equals -1. This approach effectively demonstrates the identity in three-variable calculus.
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Homework Statement



Suppose that the equation f(x,y,z)=0 can be solved for each of the three variables as a differentiable function of the other two. Prove that:

(dx/dy)(dy/dz)(dz/dx)=-1

Homework Equations





The Attempt at a Solution


In the case of two variables where one is a function of the other, dy/dx = -(df/dx)/(df/dy), but I can't figure out how this works with 3 variables.
 
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so to get you started, first we know
x=x(y,z)
y=y(z,x)
z=z(x,y)


so fa(x,y,z) = f(x,y,z(x,y))=0 the differentiating w.r.t x gives

df/dx +df/dz(dz/dx)=0
 
Thanks. I was able to figure it out from there.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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