How Do You Simplify (cos(2x))^2 Using Trigonometric Identities?

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Homework Help Overview

The discussion revolves around the expression (cos(2x))^2 and its simplification using trigonometric identities. Participants are exploring how to interpret and manipulate this expression within the context of trigonometric functions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the interpretation of (cos(2x))^2, with some suggesting it could be confused with cos^2(2x) or cos^2(4x). There is a discussion about the order of operations and the implications of the exponent on the cosine function.

Discussion Status

The conversation is ongoing, with participants clarifying the meaning of the expression and discussing potential approaches to simplifying it. Some have suggested writing it as cos^2(2x), while others are exploring the implications of different interpretations.

Contextual Notes

There appears to be some confusion regarding the nature of the problem, as participants have not clearly stated the intended goal of simplifying the expression. This lack of clarity may affect the direction of the discussion.

justine411
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Homework Statement



(cos2x)^2

Homework Equations





The Attempt at a Solution



I'm not sure if it is cos^2(2x) or cos^2(4x) or what. Should I use an identity to simplify it to make it easier to solve? Please help! :)
 
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What is there to solve? :confused:

(cos2x)^2 is just an expression.
 
In what sense is (cos(2x))2 a "problem"? What do you want to do with it?

I will say that (cos(2x))2 means: First calculate 2x, then find cosine of that and finally square that result. Notice that it is still 2x, not 4x. The fact that 2 is outside the parentheses means that it only applies to the final result.
 
HallsofIvy said:
In what sense is (cos(2x))2 a "problem"? What do you want to do with it?

I will say that (cos(2x))2 means: First calculate 2x, then find cosine of that and finally square that result. Notice that it is still 2x, not 4x. The fact that 2 is outside the parentheses means that it only applies to the final result.

Doesn't (cos(2x))2 = cos2(2x)2 = cos2(4x2) ?
 
Rhythmer said:
Doesn't (cos(2x))2 = cos2(2x)2 = cos2(4x2) ?

No. 'Cos' is a particular operation and 2x is the argument. The exponent of 2 operates on cos, not on the argument.

cos2y = cos y * cos y.

There are also particular trigonometric identites with which one should be familiar, i.e. cos (x+y) and sin (x+y).
 
You still haven't told us what the problem was! Was it to write (cos(2x))^2 in terms of sin(x) and cos(x)? I would simply be inclined to write (cos(2x))^2 as cos^2(2x).
 

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