How do you solve a differential equation for mechanical vibrations homework?

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SUMMARY

The discussion focuses on solving a differential equation related to mechanical vibrations, specifically for a mass-spring-damper system. The equation derived is 4x'' + 4x' + 37x = 0, leading to the characteristic roots r = -1/2 ± (1/2)sqrt(26)i. The position function is determined as x(t) = e^(-0.5t)(cos(0.5sqrt(26)t) + (17/sqrt(26))sin(0.5sqrt(26)t)). The initial conditions x(0) = 1 and x'(0) = 8 are used to find the constants C1 and C2.

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  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with mechanical systems involving mass, spring constants, and damping.
  • Knowledge of initial value problems and how to apply initial conditions.
  • Proficiency in using exponential and trigonometric functions in solutions.
NEXT STEPS
  • Study the method of solving second-order linear differential equations with constant coefficients.
  • Learn about the physical interpretation of damping in mechanical systems.
  • Explore the use of Laplace transforms for solving differential equations.
  • Investigate the effects of varying damping constants on system behavior.
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Students in mechanical engineering, physics, or applied mathematics who are tackling problems related to differential equations and mechanical vibrations.

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Homework Statement


A mass m=4 is attached to both a spring, with spring constant k=37, and a dash-pot with damping constant c=4.

The ball is started in motion with initial position x0=1 and initial velocity v0=8 .
Determine the position function x(t).


Homework Equations





The Attempt at a Solution


So, the differential equation would be:
4x''+4x'+37x=0
4r^2+4r+37=0
r=-(1/2)+or- (1/2)sqrt(26)i

And so,
x(t)=e^(-.5t)(C1cos(.5sqrt(26)t)+C2sin(.5sqrt(26)t))
x'(t)=-.5e^(-.5t)(C1cos(.5sqrt(26)t)+C2sin(.5sqrt(26)t))+e^(-.5t)(-.5*C1sqrt(26)sin(.5sqrt(26)t)+.5*C2sqrt(26)cos(.5sqrt(26)t))

x(0)=C1=1
x'(0)=.5sqrt(26)C2-.5C1=8
=.5sqrt(26)C2=17/2
C2=17/sqrt(26)

And so,
x(t)=e^(-.5t)(cos(.5sqrt(26)t)+(17/sqrt(26))sin(.5sqrt(26)t))


Can anyone see anything wrong with this??
 
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Hi jrsweet! :smile:

(have a square-root-: √ and try using the X2 tag just above the Reply box :wink:)

Where did your √26 come from? :confused:
 

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