How Do You Solve a Non-Equilibrium Pulley System with a 154 Degree Angle?

Click For Summary
SUMMARY

The discussion focuses on solving a non-equilibrium pulley system with a 154-degree angle, specifically determining the tension in the system, which is calculated to be 626N. Participants emphasize the importance of understanding the relationship between the positions of the masses and the geometry of the system. The conversation highlights the need to differentiate the expressions for the positions of the masses to analyze the dynamics of the system effectively. The tension in the V-shaped wire is noted to be at a minimum to maintain the sliding motion of the masses.

PREREQUISITES
  • Understanding of non-equilibrium mechanics
  • Familiarity with pulley systems and tension forces
  • Knowledge of differentiation in calculus
  • Concept of related rates in physics
NEXT STEPS
  • Study the principles of non-equilibrium mechanics in detail
  • Learn how to derive tension in pulley systems using calculus
  • Explore related rates problems in physics, particularly those involving fixed lengths
  • Investigate the geometric properties of V-shaped pulley systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in advanced mechanics and pulley system dynamics.

ashley2024
Messages
5
Reaction score
0
Homework Statement
Find the tension in the following system (see image).
Relevant Equations
Fnet = ma, Ff = uFn,
Please note that the system is not in equilibrium, and that tension must be solved for the instant where the angle is 154 degrees.

inst V.png


My attempt (correct ans is Ft = 626N)
image (4).png
 
Physics news on Phys.org
##a_1=a_2##? Sure?
 
haruspex said:
##a_1=a_2##? Sure?
Nope, but I don't really have any other ideas.
 
ashley2024 said:
Nope, but I don't really have any other ideas.
There is a simple relationship between the two, just not quite that simple.
Start with positions. If m is x from the vertical through M, the knot is y below the horizontal through m, the string connecting them has length L, and it is at θ to the vertical, write expressions for x and y and differentiate twice.
 
haruspex said:
There is a simple relationship between the two, just not quite that simple.
Start with positions. If m is x from the vertical through M, the knot is y below the horizontal through m, the string connecting them has length L, and it is at θ to the vertical, write expressions for x and y and differentiate twice.
Would this be similar to the related rates problems? Since the ropes have fixed length, it seems similar to the ladder problem where you have to differentiate its rate as it falls...
 
ashley2024 said:
Please note that the system is not in equilibrium...
Welcome, Ashley! :smile:

What makes you state that?
 
Lnewqban said:
Welcome, Ashley! :smile:

What makes you state that?
The teacher who gave this problem.
 
ashley2024 said:
The teacher who gave this problem.
Then, the tension in the V=shaped wire should be the minimum to keep masses #1 sliding toward each other.
We could then, disregard the value of the force exerted by the falling mass #2, since we know that it is plenty to have induced and to keep the sliding movements of both masses #1.
Therefore, calculating T2 seems not to be necessary.
As the system is geometrically symmetrical, there is a unique value for T1.
 
Interesting! But I don't understand why it would be the minimum though? Since its asking for the tension when the angle is 154, I assumed that the tension could be still in the process of changing.
 
  • #10
ashley2024 said:
But I don't understand why it would be the minimum though
It isn't. Don’t be distracted by that.
 
  • #11
ashley2024 said:
Would this be similar to the related rates problems? Since the ropes have fixed length, it seems similar to the ladder problem where you have to differentiate its rate as it falls...
Yes.
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
24
Views
4K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K