How Do You Solve a Vector Calculus Integral Over a Sphere?

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Homework Help Overview

The discussion revolves around evaluating a vector calculus integral over the surface of a sphere. The original poster presents a problem involving the double integral of the dot product of a position vector and a unit normal vector over the sphere's surface.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of the unit normal vector and its calculation. There is a discussion about whether to use a double or triple integral for the evaluation, with some suggesting that a double integral is appropriate. Questions arise regarding the correct setup of the integral and the area element in spherical coordinates.

Discussion Status

Participants are actively discussing the setup of the integral and the appropriate use of spherical coordinates. Some guidance has been offered regarding the area element and the need to clarify the integral's limits. There is no explicit consensus on the correct approach yet, as various interpretations are being explored.

Contextual Notes

Some participants mention the surface area of the sphere as a known result, but the focus remains on explicitly solving the integral as practice. There are references to tutor notes and external resources for further clarification on spherical coordinates and integration techniques.

Hoofbeat
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Anyone take a look at this vector calculus question for me:

=====
Q. If n is the uni normal to the surface S, evaluate Double Integral r.n dS over the surface of a sphere of radius 'a' centred at the origin.
=====

So I did:

r = (x,y,z)
Sphere: x^2 + y^2 + z^2 = a^2

let f = x^2 + y^2 + z^2

n = gradf / |grad f|

therefore n = (x,y,z)/a

n.r = a

Now how do I proceed with the integral? I thought it would just be

int(2pi->0) int (pi->0) int(a->0) a r.dr.d[theta].d[phi]

which gives the answer [pi]^2.[a]^3 which really doesn't look right! I think it's the actual integral I've made a mistake with! HELP! I HATE VECTOR CALCULUS [and I really need to learn to use latex!]
 
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Isnt n = \frac{2x,2y,2z}{|gradF|}?
 
Btw, I know that a simple way to solve my problem is just to use the fact that the surface area of the sphere is 4*pi*a^3, but I want to solve the integral explicitly (as practise). Have found my tutor's notes and she found the 'area element' to be a*sin^2*theta*d[theta]*d[phi] and thus carried out a double integral. Could someone explain this please?
 
whozum said:
Isnt n = \frac{2x,2y,2z}{|gradF|}?


Yes but the |gradF| on the bottom gives you a factor of 2, so it cancels :frown: Having found my tutor's notes I know that I'm doing fine up until the integral and I shouldn't be doing it as a triple integral, but rather a double integral as I've explained in my above post.
 
there's a few spherical coordinate problems here including derivations that are explained pretty well.

http://tutorial.math.lamar.edu/AllBrowsers/2415/TISphericalCoords.asp
 
Last edited by a moderator:
thanks. they're still carrying out triple integrals though, whereas I should only be doing a double integral :s
 
I'd help you out but I don't have my calc 3 book to recall the specific steps in deriving spherical coordinates, but I am pretty sure spherical coordinates only works in triple integrals since it uses 3 parameters, p,theta,phi.

Im probably not the person to helping you with this. Sorry.
 
There is a section on any kind of integration on the left hand navigation menu if you want to look around yourself.

edit: http://tutorial.math.lamar.edu/AllBrowsers/2415/SurfaceIntegrals.asp
Example 2
 
Last edited by a moderator:
Hoofbeat said:
Anyone take a look at this vector calculus question for me:

=====
Q. If n is the uni normal to the surface S, evaluate Double Integral r.n dS over the surface of a sphere of radius 'a' centred at the origin.
=====

So I did:

r = (x,y,z)
Sphere: x^2 + y^2 + z^2 = a^2

let f = x^2 + y^2 + z^2

n = gradf / |grad f|

therefore n = (x,y,z)/a

n.r = a

Now how do I proceed with the integral? I thought it would just be

int(2pi->0) int (pi->0) int(a->0) a r.dr.d[theta].d[phi]

which gives the answer [pi]^2.[a]^3 which really doesn't look right! I think it's the actual integral I've made a mistake with! HELP! I HATE VECTOR CALCULUS [and I really need to learn to use latex!]
SOLUTION HINTS:
Problem requires evaluation of {∫ ∫ r⋅dA} over Surface of Sphere of Radius "a":
The Unit Area normal element on the Sphere's surface is given by:
dA = r2sin(φ)⋅dθ⋅dφ⋅r/|r|
::: ⇒ ∫ ∫ r⋅dA = ∫ ∫ r⋅r2sin(φ)⋅dθ⋅dφ⋅r/|r| =
= ∫ ∫ r3sin(φ)⋅dθ⋅dφ = ?
The above Double Integral should be evaluated at constant (r = a) for integration limits {0 ≤ θ ≤ 2*π} and {0 ≤ φ ≤ π}.

For more info, see Equation #14 at:
http://mathworld.wolfram.com/SphericalCoordinates.html


~~
 
Last edited:

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