How Do You Solve for Conditional Variance with a Given Joint Distribution?

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To solve for the conditional variance Var[Y|X=x] given the joint distribution f(x,y) = 2x for 0<x<1 and x<y<x+1, first determine the conditional density f(y|X=x). This involves calculating the marginal density of X and then using it to find the conditional density. Once f(y|X=x) is established, the conditional variance can be computed using the formula Var[Y|X=x] = E[Y^2|X=x] - (E[Y|X=x])^2. Understanding these steps is crucial for successfully solving the problem. This approach will help in preparing for the probability exam effectively.
waealu
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I am working on studying for a probability exam and I just came across conditional variance, but I can't find anything in my materials for how to solve it.

If I want to find the conditional variance of Y given that X=x, or Var[Y|X=x], how would I solve it? I am given a continuous distribution function of:

f(x,y) = 2x, for 0<x<1, x<y<x+1
otherwise 0.

How do I set up this question?

Thanks!
 
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waealu said:
I am working on studying for a probability exam and I just came across conditional variance, but I can't find anything in my materials for how to solve it.

If I want to find the conditional variance of Y given that X=x, or Var[Y|X=x], how would I solve it? I am given a continuous distribution function of:

f(x,y) = 2x, for 0<x<1, x<y<x+1
otherwise 0.

How do I set up this question?

Thanks!

Set it up the standard way: first determine the conditional density f(y|X=x).

RGV
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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