How Do You Solve Particle Motion Problems in Physics Exams?

AI Thread Summary
The discussion focuses on solving particle motion problems in physics exams, specifically referencing a past exam question. The participant expresses uncertainty about their performance and shares their calculations, including formulas for tension, velocity, and acceleration. Feedback highlights the importance of maintaining symbolic representation until the final answer and points out errors in the setup for calculating tension. Additionally, there is a reminder to consider vertical acceleration in circular motion problems. The conversation emphasizes the need for careful algebraic manipulation and clarity in problem-solving approaches.
Woolyabyss
Messages
142
Reaction score
1

Homework Statement


So I just sat an exam today and I'm not sure how I did in this question. I think I did bad in it.

http://www.examinations.ie/archive/exampapers/2014/LC020GLP000EV.pdf

Its question 8

Homework Equations


F = mv^2/r

v=ωr

t=2(pi)r/v

The Attempt at a Solution



Q9

(a)

T=2(pi)r/v ...... 0.4pi = 2pi(2)/v

solving for v ... 10 m/s

v = rω

10 = 2ω ...... ω = 5 rad/s

a =v^2/r

a = 10^2/2 = 50 m/s^2

(i) 5 rad/s
(ii) 10 m/s
(iii) 50 m/s^2(B)

(i) r = 1sin30 = 0.5m

(ii) splitting its weight into components perpendicular and parallel to string

parallel force = 2gcos30 = √3 g N

Tension = parallel force
Tension = √3 g N

(iii) F = mv^2/r

√3 g = 2v^2/.5
solving for v = 2.06 m/s

v = ωr

2.06 = .5ω

ω = 4.12 rad/s
 
Last edited by a moderator:
Physics news on Phys.org
hmmm... well what exactly are you looking for? someone to check your work? If you're looking for that, the LEAST you can do is keep it all algebraic (symbolic) until the end. Too many numbers here.

That being said, I didn't work through the first one, but ii) in solving for the tension, your setup is wrong, which means you probably got the wrong answer. What do you know about the vertical acceleration if it's constrained to moving along that circle? What is the value of that component?

Now what else can you say that value is equal to?
 
also, you labeled it Q9, not Q8.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top