How Do You Solve Sigma Notation with a Different Starting Index?

Click For Summary

Discussion Overview

The discussion focuses on solving sigma notation problems with a starting index different from 1, specifically addressing the expression involving the summation from i=3 to n of (i^2 - 3). Participants explore how to adjust the general term when changing the starting index and share their approaches to rewriting the summation.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses uncertainty about solving sigma notation when the index starts at 3 instead of 1.
  • Another participant suggests that to change the starting index from 3 to 1, the general term must also be adjusted by the same number of index units in the opposite direction.
  • A different participant attempts to write the summation with the adjusted index but finds the formatting challenging.
  • One participant proposes writing out the terms of the summation starting from 1 and discarding the first two terms to understand the solution better.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method to adjust the summation for a different starting index, and multiple approaches are presented without resolution.

Contextual Notes

Some participants' suggestions depend on the interpretation of how to shift the index and adjust the general term, which may not be universally agreed upon.

haydn
Messages
26
Reaction score
0
I understand how to solve sigma notation problems where the index variable is equal to 1, but how would I solve a problem like this??

n
[tex]\Sigma[/tex] (i2-3)
i=3

If i was equal to 1 I would be able to solve this, but I'm not sure what to do since it is equal to 3.

Thanks!
 
Physics news on Phys.org
You want to start the index at i=1 instead of i=3, and you want to know how to change the general term of i2-3.

If you shift the initial index from 3 to 1, then you need to change the general term the same number of index units in the other direction. That is how you compensate for the change to the index variable.

I'm searching for the proper latex formatting in this message tool set but cant' find it.
Summation from 3-2 to n, of (i+(3-1))2-3
You know you wanted to change the starting index value by 2 units to the left, so you change the general term by 2 units to the right.
 
I just need to try this:

[tex]^{n}_{1}[/tex][tex]\sum[/tex](i+2)2-3

Not exactly the way I hoped it would look, but it is very close; maybe readable by understanding reading members.
 
Last edited:
haydn said:
I understand how to solve sigma notation problems where the index variable is equal to 1, but how would I solve a problem like this??

n
[tex]\Sigma[/tex] (i2-3)
i=3

If i was equal to 1 I would be able to solve this, but I'm not sure what to do since it is equal to 3.

Thanks!

Think about it, if we have

[tex]\sum_{i=1}^{n} i^{2} - 3[/tex]

Now let's write out the first term, we now have

[tex]\sum_{i=1}^{n} i^{2} - 3 = (1^{2} - 3) + \sum_{i=2}^{n} i^{2} - 3 = -2 + \sum_{i=2}^{n} i^{2} - 3[/tex]

Keep writing out the terms until you get to your sum i.e. the one that starts from 3.

Do you see what the answer is?
 
haydn said:
I understand how to solve sigma notation problems where the index variable is equal to 1, but how would I solve a problem like this??

n
[tex]\Sigma[/tex] (i2-3)
i=3

If i was equal to 1 I would be able to solve this, but I'm not sure what to do since it is equal to 3.

Thanks!
i starts and 3, it is not "equal to 3". If you were able to do it with i starting at 1, then one way to do this problem is to write out what you would have if i started with 1, then throw away the first two terms!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
8K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K