- #1
Brianna V
- 3
- 0
How do I evaluate the sum of this sigma notation problem?
20
∑ k
k=10
Normally, I would think to use the theorem for the sum of the first n integers:
n
∑ k = n(n+1)/2
k=1
I don't know how to do this, however, since the lower limit is k=10, not k=1.
My professor wrote this note on the board for the problem. It gives the answer, but I still don't understand it. If you do, could you explain? Thanks!
20...20...9
∑ k = ∑ - ∑ k
k=10 k=1 k=1
20(21)/2 - 9(10)/2 = 165 <-- (The answer)
20
∑ k
k=10
Normally, I would think to use the theorem for the sum of the first n integers:
n
∑ k = n(n+1)/2
k=1
I don't know how to do this, however, since the lower limit is k=10, not k=1.
My professor wrote this note on the board for the problem. It gives the answer, but I still don't understand it. If you do, could you explain? Thanks!
20...20...9
∑ k = ∑ - ∑ k
k=10 k=1 k=1
20(21)/2 - 9(10)/2 = 165 <-- (The answer)