How Do You Solve the Integral of t * csc^2(t) dt?

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To solve the integral of t * csc^2(t) dt, integration by parts is suggested, with u = t and dv = csc^2(t) dt. The resulting expression includes -t * cot(t) and requires finding the antiderivative of -cot(t). A hint is provided to express cotangent in terms of other trigonometric functions, facilitating substitution. The integral of cot(x) is identified as log(sin(x)), which can be derived through a substitution method. The discussion emphasizes the importance of recognizing singularities and symmetry in the integral's evaluation.
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Homework Statement


integral (t * csc^2 (t) ) dt


Homework Equations





The Attempt at a Solution



t * -cot (t) - integral( 1 * -cot (t)) u= t dv= csc^2(t)
du= 1 v= - cot (t)
-t * cot(t) - ? I don't understand how to find the antiderivative of -cot(t)
 
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Integration by parts is the way I'd also go about this.

Hint: In terms of other trig functions, what is cotangent equal to? You should end up with something that is solvable by substitution.
 
The integral contains singularities whenever sin(x)=0, or x=n PI

If it's an integral over -T, to T then the integral is zero (by symmetry)
 
\cot x = \frac{\cos x}{\sin x}

\int \cot x dx = \int \frac{\cos x}{\sin x} dx.

let u= sin x, then du = cos x dx

\int \frac{1}{u} du = \ln u + C = \ln (\sin x) + C
 
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