How Do You Solve the Limit Using the Quotient Law?

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To solve the limit lim (1/x - 1/3) / (x-3) as x approaches 3, it is essential to combine the fractions in the numerator using a common denominator. Attempting to cancel (x-3) directly leads to an indeterminate form of 0/0, which complicates the solution. Instead, simplifying the numerator first allows for proper evaluation of the limit. The correct approach ultimately reveals that the limit equals -1/9. Understanding fraction manipulation is key to resolving similar limit problems effectively.
Alice7979
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Homework Statement


lim (1/x - 1/3) / (x-3)
x->3

Homework Equations

The Attempt at a Solution


I tried to cancel the bottom (x-3) out by multiplying the top by 3/3 and x/x and then got ((3-x)/3x)/(x-3) but ended with 0/0 and the right answer is -1/9. The top part is confusing me.
 
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Alice7979 said:

Homework Statement


lim (1/x - 1/3) / (x-3)
x->3

Homework Equations

The Attempt at a Solution


I tried to cancel the bottom (x-3) out by multiplying the top by 3/3 and x/x and then got ((3-x)/3x)/(x-3) but ended with 0/0 and the right answer is -1/9. The top part is confusing me.
Combine the two fractions in the numerator, and then simplify. This problem isn't much more than an exercise in working with fractions.
 
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Like @Mark44 said, find a common denominator between ## \frac 1 x \text{ and } \frac 1 3 ##. Similar to if you were adding the fractions ## \frac 1 7 \text{ and } \frac 1 3 ##
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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