How do you take the Fourier transform of sin(t)/t using Parseval's Theorem?

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Homework Help Overview

The discussion revolves around evaluating an integral using Parseval's theorem, specifically focusing on the function x(t) = (sin(t)cos(10t))/(pi*t) and its Fourier transform properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Parseval's theorem and the Fourier transform of the function sin(t)/t. There are attempts to manipulate the function using trigonometric identities and inquiries about the existence of a Fourier transform for sin(w)/w.

Discussion Status

Participants are exploring various approaches to find the Fourier transform of sin(t)/t. Some guidance has been provided regarding the existence of the transform and references to transform tables. There is an acknowledgment of a hint related to the inverse Fourier transform of a specific function.

Contextual Notes

There is mention of potential confusion regarding the definition of sinc(x) and its variations in different contexts, which may affect the interpretation of the Fourier transform.

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Homework Statement



Evaluate INT(|X(t)|^2) dt using parsevals theorem

where x(t) = (sin(t)cos(10t))/(pi*t)


Homework Equations



parsevals theorem: int(|f(t)|^2 dt = (1/2*pi)INT(|F(W)|^2 dw



The Attempt at a Solution



So I've tried several attempts at this problem and this is my latest:

first I use the fact that sin(x)*cos(y) = (sin(x+y)+sin(x-y)) /2
to get sin(t)cos(10t)/pi*t = (sin(t+10t) + sin(t - 10t))/(2*pi*t)

then I split it up into : sin(11t)/2t*pi + sin(-9t)/2t*pi

then what I was going to do was take the Fourier transform of each function here however, I can't figure out how in the world to take the Fourier transform of sin(t)/t

anyone have any ideas? thanks!
 
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Do you know a function whose Fourier transform is [itex]\sin(\omega)/\omega[/itex]?
 
I checked on my transform table and looked around online a little and didn't see any transform that equals sin(w)/w. If there was i'd use the f(w) <-> F(t) rule and then it could work for me. Does that transform exist?
 
Hint:

Compute the (inverse) Fourier transform of f(x), defined as:

f(x) = 1 for -L < x < L,

otherwise f(x) = 0
 
Yes, it exists and is one of the most fundamental transforms! If your table doesn't have it, I would get another table (seriously). Count Iblis' hint is right on the money.

By the way, [itex]\sin(x)/x[/itex] is sometimes called [itex]sinc(x)[/itex], so look in your table for that. Caution: some authors define [itex]sinc(x) = \sin(\pi x)/(\pi x)[/itex].
 
Last edited:
ooohhhh now it makes sense! thank you! XD
 

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