How Does a 1% Increase in Dimensions Affect the Volume of a Slab?

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SUMMARY

The discussion focuses on calculating the increase in volume of a slab when its dimensions—width, length, and height—each increase by 1%. The volume of the slab is defined by the formula V = xyz. When each dimension is increased by 1%, the new volume becomes V = (1.01x)(1.01y)(1.01z), which simplifies to V = (1.01)^3 xyz. This results in an increase in volume of approximately 3.03% from the original volume V_0.

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abhay1
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Fig.(1) shows a slab whose volume V is given by
V = xyz.
If the width, the length and the height of the slab, each increases by 1%, what is the
increase in its volume?
 
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Re: partial differential equations

abhay said:
Fig.(1) shows a slab whose volume V is given by
V = xyz.
If the width, the length and the height of the slab, each increases by 1%, what is the
increase in its volume?
What figure?

I'm going guess that one corner of your slab is at the origin and everything is all nice and perpendicular.

So: [math]V_0 = xyz[/math] (Your original volume.)

Now, if we add 1% to x then we have x + 0.01x = 1.01x. Similar for the other dimensions. So [math]V = (1.01x)(1.01y)(1.01z) = (1.01)^3 xyz = (1.01)^3 V_0[/math]

What is the increase in volume here?

-Dan
 

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