How does an index of refraction affect the EM field?

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The discussion centers on how the index of refraction affects electromagnetic (EM) fields in a homogeneous material. It is established that when transitioning from a vacuum to a medium with a refractive index n, the wavelength and wave vector change according to λ → λ₀/n and k → k₀n, respectively. The participants agree that these changes in velocity, wavelength, and related quantities are sufficient to derive the EM field equations in the medium. It is clarified that the EM wave equation is derived from Maxwell's equations, which relate spatial and temporal variations, and that the source of the wave determines its wavelength and frequency. The conversation concludes with confirmation of the understanding that the only difference in the equations for the medium is the substitution of permittivity and permeability values.
2sin54
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Hello. Say I have some refraction index n in a homogeneous material. Say I also have equations for the EM field (E and B vectors). Is it true to say that all that changes is the wavelength
\lambda \to \frac{\lambda_0}{n}
and consequently the wave vector
k \to k_0 n ?
Is it enough to account for this wavelength change to derive the EM field equations in a homogeneous material of refraction index n?
 
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The equation of a one dimensional traveling wave is
2A/∂x2 = (1/v2)∂2A/∂t2

where v is the velocity of the wave.

Maxwell's wave equation is

2E/∂x2 = (εμ) ∂2E/∂t2

Where ε and μ are the permittivity and permeability of the material respectively

recognizing that this is a traveling wave equation the velocity of the wave would be

v= 1/(εμ)½

in a vacuum v =c = 1/(ε0μ0)½
 
gleem said:
The equation of a one dimensional traveling wave is
2A/∂x2 = (1/v2)∂2A/∂t2

where v is the velocity of the wave.

Maxwell's wave equation is

2E/∂x2 = (εμ) ∂2E/∂t2

Where ε and μ are the permittivity and permeability of the material respectively

recognizing that this is a traveling wave equation the velocity of the wave would be

v= 1/(εμ)½

in a vacuum v =c = 1/(ε0μ0)½
Thank you for the reply. Yes, the velocity changes and consequently both the wavelength and the wave number change as well. So changing the velocity, wavelength and all the functions of these quantities of the EM wave should be sufficient to get the equations of the EM wave in a material, is that correct?
 
2sin54 said:
So changing the velocity, wavelength and all the functions of these quantities of the EM wave should be sufficient to get the equations of the EM wave in a material, is that correct?

I do not understand your question. The EM wave equation is derived directly for Maxwell's four equations. It relates the spatial variation to the time variation. The solution of the wave equation then provides the velocity. The wavelength and frequency are determined by the source of the wave not the wave equation itself.
 
gleem said:
I do not understand your question. The EM wave equation is derived directly for Maxwell's four equations. It relates the spatial variation to the time variation. The solution of the wave equation then provides the velocity. The wavelength and frequency are determined by the source of the wave not the wave equation itself.
Sorry for not being clear. I meant to say that I have the equations for the EM wave (in terms of E and B) in a vacuum (n = 1) and I wish to determine the equations for the same wave when it travels through a homogeneous medium (n != 1).
 
The only difference is that ε0μ0 is replaced by εμ for the particular medium you are interested in remember

μ = Kmμ0 Km = relative permeability

ε= Keε0 = Ke = dielectric constant.(relative permittivity )
 
gleem said:
The only difference is that ε0μ0 is replaced by εμ for the particular medium you are interested in remember

μ = Kmμ0 Km = relative permeability

ε= Keε0 = Ke = dielectric constant.(relative permittivity )
Thank you. That more or less confirms my thoughts.
 

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