How does angular velocity affect the density of water in a rotating container?

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Discussion Overview

The discussion revolves around the effects of angular velocity on the density of water in a rotating container. Participants explore the theoretical implications of centrifugal force on water density, particularly under varying conditions of motion.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant proposes that water density will increase due to centrifugal force causing molecules to move closer together.
  • Another participant argues that water can be considered a non-compressible fluid under many conditions, suggesting that density would remain approximately 1 gram per cubic centimeter unless extreme conditions are present.
  • A participant questions whether water can still be considered non-compressible if the container is moving at a linear velocity greater than a certain threshold.
  • It is noted that water is slightly compressible and that the density is related to pressure through a specific compressibility equation.
  • A suggestion is made to calculate pressure variation to determine how density changes, emphasizing that changes in density are typically very small even in a centrifuge.

Areas of Agreement / Disagreement

Participants express differing views on whether water can be treated as non-compressible in the context of the problem, indicating that multiple competing views remain unresolved.

Contextual Notes

Limitations include assumptions about the conditions under which the fluid is analyzed, the dependence on definitions of compressibility, and the scope of the problem regarding extreme velocities.

bartekac
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Hi,

I was recently thinking about a problem which I have no idea how to solve.
A full water container with volume V is hanged on a rope with length L (mass of the rope is negligible). It then starts to revolute around the point where the rope is hooked (circular motion, circle with radius L) with angular velocity ω.
Express the water density ρ as a function of V, L, and ω.

Thanks in advance for any help.
 
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Is this a homework problem?

Chet
 
No, it is not.
I was just concerned that I have actually no idea how to approach it.
 
bartekac said:
No, it is not.
I was just concerned that I have actually no idea how to approach it.
OK. Tell us in words what you think will be happening.

Chet
 
Ok.
I suppose the water density will increase as a result of centrifugal force causing the molecules to move closer to one another.
 
Water, under a wide variety of conditions, can be considered a non-compressible fluid. If your experiment is to be conducted in this range of conditions then p would simply be the density of water (about 1 gram per cubic centimeter). If your experiment is under more extreme conditions, it would be helpful to know what those conditions are.
 
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In general, what interests me here is how to approach the problem of calculating the compression of a fluid in the described situation.
Can water still be considered non-compressible if the container was, for instance, moving with a linear velocity L\omega>\frac{1}{4}c?
 
Water is slightly compressible. The density of a fluid is related to the pressure on the fluid by
$$\frac{1}{\rho}\frac{d\rho}{dp}=β$$
where β is a physical property of known as the compressibility. You can look up the compressibility of water on Google for room temperature. So, if you can calculate how the pressure is varying spatially as a result of how you are moving the bucket, you can determine how the density is varying. You can determine the pressure variation by applying Newton's second law to the fluid locally.

In any event, the change in density will typically be very small even in a centrifuge.

Chet
 
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