How Does Biaxial Force Affect Stress and Strain in a Rectangular Bar?

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The discussion focuses on analyzing the effects of biaxial forces on a rectangular bar's stress and strain. Given the bar's dimensions and material properties, the average normal stresses in the x and y directions were calculated, resulting in σx = 1x10^9 N/m² and σy = 1x10^8 N/m², with no stress in the z direction. The calculated strains were ∈x = 9.7, ∈y = -2, and ∈z = -3.3. A mistake was identified in the calculation of the new dimension in the x-direction, as it resulted in a negative length, indicating an error in applying the Young's modulus. The discussion emphasizes the importance of correctly applying the equations for stress and strain to avoid nonsensical results.
Confusedbiomedeng

Homework Statement


consider the rectangular bar undeformed a=b=2cm and c=20cm . The elastic modulus of the bar material is E=100 Gpa and its poissons ratio is u=0.3. The bar is subjected to biaxial forces in the x and y directions such that Fx=Fy=0.4x106 N and that Fx is tensile while Fy is compressive . Assuming that the bar material is linear elastic
Determine:
i)the average normal stresses σx,σy and σz developed in the bar
ii)the average normal strains ∈x,∈y and ∈z
iii)dimension c' of the bar in the x-direction after deformation

Homework Equations


σx=fx/(ab) σy=Fy/(cb) σz=no force no stress
∈x=1/E(σx-u(σy+oz))
∈y=1/E(σy-u(σx+σz))
∈z=1/E(σz-u(σx+σy))
∈=ΔL/L

The Attempt at a Solution


σx=0.4x106/0.02x0.02=1x109
σy=0.4x106/0.2x0.02=1x108
σz=no force no stress

using above equation
∈x=9.7
∈y= -2
∈z= -3.3

new c dimension
.-3.3=ΔL/0.2
-0.66
0.2+-0.66= -0.46
however you can't have negative length??
can anyone show me where I am going wrong?
 
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You forgot to divide by the Young's modulus, and the stress in the y direction is negative.
 

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