How Does Biaxial Force Affect Stress and Strain in a Rectangular Bar?

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SUMMARY

The discussion focuses on the effects of biaxial forces on stress and strain in a rectangular bar with dimensions a=b=2cm and c=20cm, elastic modulus E=100 GPa, and Poisson's ratio u=0.3. The applied forces are Fx=0.4x10^6 N (tensile) and Fy=0.4x10^6 N (compressive). The calculated average normal stresses are σx=1x10^9 Pa, σy=1x10^8 Pa, and σz=0 Pa, while the average normal strains are ∈x=9.7, ∈y=-2, and ∈z=-3.3. The new dimension in the x-direction after deformation is incorrectly calculated due to a misunderstanding of the relationship between stress, strain, and Young's modulus.

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Homework Statement


consider the rectangular bar undeformed a=b=2cm and c=20cm . The elastic modulus of the bar material is E=100 Gpa and its poissons ratio is u=0.3. The bar is subjected to biaxial forces in the x and y directions such that Fx=Fy=0.4x106 N and that Fx is tensile while Fy is compressive . Assuming that the bar material is linear elastic
Determine:
i)the average normal stresses σx,σy and σz developed in the bar
ii)the average normal strains ∈x,∈y and ∈z
iii)dimension c' of the bar in the x-direction after deformation

Homework Equations


σx=fx/(ab) σy=Fy/(cb) σz=no force no stress
∈x=1/E(σx-u(σy+oz))
∈y=1/E(σy-u(σx+σz))
∈z=1/E(σz-u(σx+σy))
∈=ΔL/L

The Attempt at a Solution


σx=0.4x106/0.02x0.02=1x109
σy=0.4x106/0.2x0.02=1x108
σz=no force no stress

using above equation
∈x=9.7
∈y= -2
∈z= -3.3

new c dimension
.-3.3=ΔL/0.2
-0.66
0.2+-0.66= -0.46
however you can't have negative length??
can anyone show me where I am going wrong?
 
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You forgot to divide by the Young's modulus, and the stress in the y direction is negative.
 

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