How Does Changing Temperatures Affect Carnot Engine Efficiency?

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Homework Help Overview

The discussion revolves around the efficiency of a Carnot heat engine operating between two temperatures, Th and Tc. The original poster presents a series of questions related to the efficiency calculations and the impact of temperature changes on that efficiency.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculation of efficiency using the Carnot equation and discuss how to determine the rate of change of efficiency with respect to temperature changes. Questions arise about the appropriate methods for calculating derivatives and whether assumptions about temperature dependencies are valid.

Discussion Status

Some participants have provided guidance on using derivatives to find rates of change, while others suggest alternative approaches to calculate efficiency changes directly. The discussion includes attempts to clarify the relationship between temperature changes and efficiency without reaching a definitive consensus on the best method.

Contextual Notes

Participants are working within the constraints of a homework assignment, which includes specific temperature values and asks for changes in efficiency based on those temperatures. There is an ongoing exploration of whether the change in efficiency depends on the temperature Tc.

JSGhost
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Homework Statement


A Carnot heat engine operates between temperatures Th and Tc.
(a) If Th = 515 K and Tc = 363 K, what is the efficiency of the engine?
0.30 Your answer is correct.

(b) What is the change in its efficiency for each degree of increase in Th above 515 K?
? K-1

(c) What is the change in its efficiency for each degree of change in Tc?
? K-1

(d) Does the answer to part (c) depend on Tc?
Yes or No?

Explain.


Homework Equations


e_c = 1 - T_c/T_h


The Attempt at a Solution



(a)
T_h = 515k
T_c = 363k
e_c = 1 - T_c/T_h = 1 -363k/515k = 0.2951456311 = 0.30

I'm don't know how to start part (b). Do I use the same equation or a different one?
 
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You want to find the rate of change of the efficiency e with respect to Th. Rate of change is also known as ...? (Hint: It's the "D" word.)
 
So do the derivative of e = 1 - T_c/T_h ?
 
Yes.
 
e = 1 - T_c/T_h

How do you do the derivative of that equation?

dE = -ln(T_h/T_c) ?
 
Would it help if you said let x = TC and wrote

e = 1 - x/TH?

Can you find de/dx ?
 
Actually I did not have to do the derivative. It was so simple roflol.

b) Increase T_h by one and calculate the efficiency

1 - 363/516= 0.2965

calculate difference from the original efficiency

0.2965-0.2951=.0014

c) Decrease T_c by one and calculate

1 - 362/515= 0.2971

Now find the difference

.2951 - .2971= 0.002

d) No
 

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